NEET and AIPMT NEET Physics Motion in A Straight Line MCQ Questions Solved


 

A ball is thrown upward with a certain speed. It passes through the same point at 3 second and 7 second from the start. The maximum height achieved by the ball is

1.  500 m

2.  250 m

3.  125 m

4.  450 m

Concept Videos :-

#26-Equations-for-Uniform-Acceleration
#27-Equations for Uniform Acceleration 28Calculus Method29
#28-Sign Convention
#29-Solved Examples 16
#31-Solved-Examples-18
#32-Solved Examples 19
#33-Solved Examples 20
#34-Solved-Examples-21
#35 Solved Examples 22
#30-Solved Examples 17

Concept Questions :-

Uniformly accelerated motion

(3)                    

Time to reach highest point after 3sec = 7-32=2sec.

Time to reach highest point from ground = 3+2 = 5sec.

As upward and downward motion are symmetric [Time taken from AB is same as time taken from BC]

So, time to reach highest point is 5s. Same time is required to reach from B to ground.

For downward motion,

u=0a=gt=5sh=12gt2=12×10×52=125 m

Difficulty Level:

  • 16%
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  • 6%
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Concept Videos :-

#26-Equations-for-Uniform-Acceleration
#27-Equations for Uniform Acceleration 28Calculus Method29
#28-Sign Convention
#29-Solved Examples 16
#31-Solved-Examples-18
#32-Solved Examples 19
#33-Solved Examples 20
#34-Solved-Examples-21
#35 Solved Examples 22
#30-Solved Examples 17

Concept Questions :-

Uniformly accelerated motion

a=dvdt=dvds×dsdt=v×dvds

Difficulty Level:

  • 42%
  • 21%
  • 24%
  • 15%
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Concept Videos :-

#4-Solved Examples 1
#5-Solved-Examples-2
#6-Solved-Examples-3
#7-Solved-Examples-4
#1-Understanding Position
#2-Understanding Path Length
#3-Understanding Displacement

Concept Questions :-

Distance and displacement

Difficulty Level:

  • 56%
  • 17%
  • 24%
  • 5%
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Concept Videos :-

#45-Relative motion
#46-Relative motion-1
#47-Relative motion-2
#48-Relative motion-3
#49-Relative motion-4
#50-Relative motion-5

Concept Questions :-

Relative motion in 1-D

(1)

 

Motion of A wrt B

Relative velocity of A wrt B = VA - VB                                                =v- (vcos60° )                                                 = v/2

 Time =av2=2av

Difficulty Level:

  • 43%
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  • 21%
  • 9%
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Concept Videos :-

#42 Non Uniform Acceleration
#43 Solved Examples 29
#44 Solved Examples 30

Concept Questions :-

Non-uniform acceleration

(1)

t=x+3x=t-32At t=0 sec, x1=9mAt t=6 sec, x2=9mDisplacement=x2-x1=0

Difficulty Level:

  • 60%
  • 14%
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  • 14%
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Concept Videos :-

#42 Non Uniform Acceleration
#43 Solved Examples 29
#44 Solved Examples 30

Concept Questions :-

Non-uniform acceleration

Difficulty Level:

  • 23%
  • 12%
  • 64%
  • 3%
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Concept Videos :-

#26-Equations-for-Uniform-Acceleration
#27-Equations for Uniform Acceleration 28Calculus Method29
#28-Sign Convention
#29-Solved Examples 16
#31-Solved-Examples-18
#32-Solved Examples 19
#33-Solved Examples 20
#34-Solved-Examples-21
#35 Solved Examples 22
#30-Solved Examples 17

Concept Questions :-

Uniformly accelerated motion

Distance travelled in t second,

Here, initial velocity u=0h=gt22                                                         ......        (1)Distance travelled in nth second = u +a2(2n -1)Distance travelled in last second= 0 + g2(2t-1) =9h25     ..............(2)Equating h from equation 1 and 225g(2t-1)18=gt229t2 -50t +25 =0Solving for t,t =50 ±502-4×9×252×9 = 1018s or 5 sTime has to be greater than 1 second, so  t=5sPutting value of t in eqn. 1h=g522 = 122.5 m

Difficulty Level:

  • 14%
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A point moves in a straight line under the retardation av2. If the initial velocity is u, the distance covered in 't' seconds is-

1.  aut

2.  1aln aut

3.  1aln 1+aut

4.  a ln aut

Concept Videos :-

#42 Non Uniform Acceleration
#43 Solved Examples 29
#44 Solved Examples 30

Concept Questions :-

Non-uniform acceleration

Difficulty Level:

  • 16%
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  • 54%
  • 6%
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Concept Videos :-

#26-Equations-for-Uniform-Acceleration
#27-Equations for Uniform Acceleration 28Calculus Method29
#28-Sign Convention
#29-Solved Examples 16
#31-Solved-Examples-18
#32-Solved Examples 19
#33-Solved Examples 20
#34-Solved-Examples-21
#35 Solved Examples 22
#30-Solved Examples 17

Concept Questions :-

Uniformly accelerated motion

 

(2)

 

Upward journey                                                                   Downward journey

                                      

Net acceleration = -(a+g)                                          Net acceleration = g - a
-ve indicates retardation

 

tv= 2hg+atD= 2hg-atUTD= g-ag+a= 812= 23

Difficulty Level:

  • 39%
  • 37%
  • 16%
  • 10%
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Concept Videos :-

#45-Relative motion
#46-Relative motion-1
#47-Relative motion-2
#48-Relative motion-3
#49-Relative motion-4
#50-Relative motion-5

Concept Questions :-

Relative motion in 1-D

 

Difficulty Level:

  • 15%
  • 51%
  • 27%
  • 9%
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