The acceleration of a moving body can be found from: 

(1) Area under the velocity-time graph

(2) Area under the distance-time graph

(3) Slope of the velocity-time graph

(4) Slope of the distance-time graph

Subtopic:  Graphs |
 75%
From NCERT
PMT - 1981
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The initial velocity of a particle is u (at t = 0) and the acceleration f is given by at. Which of the following relation is valid 

1. v=u+at2

2. v=u+at22

3. v=u+at

4. v = u

Subtopic:  Non Uniform Acceleration |
From NCERT
PMT - 1981
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The initial velocity of the particle is 10 m/sec and its retardation is 2 m/sec2. The distance moved by the particle in 5th second of its motion is 

(1) 1 m

(2) 19 m

(3) 50 m

(4) 75 m

Subtopic:  Uniformly Accelerated Motion |
 59%
PMT - 1976
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The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s2. The distance covered by the body in the 5th second of its motion is  

(1) 25 m

(2) 35 m

(3) 50 m

(4) 85 m

Subtopic:  Uniformly Accelerated Motion |
 82%
PMT - 1994
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The position of a particle moving in the XY plane at any time t is given by x=(3t26t) metres. Select the correct statement about the moving particle from the following.

1. The acceleration of the particle is zero at t = 0 second
2. The velocity of the particle is zero at t = 0 second
3. The velocity of the particle is zero at t = 1 second
4. The velocity and acceleration of the particle are never zero

Subtopic:  Instantaneous Speed & Instantaneous Velocity |
 71%
From NCERT
PMT - 1995
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If body having initial velocity zero is moving with uniform acceleration 8 m/sec2 , then the distance travelled by it in fifth second will be  

(1) 36 metres

(2) 40 metres

(3) 100 metres

(4) Zero

Subtopic:  Acceleration |
 85%
PMT - 1996
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A body starts from rest from the origin with an acceleration of 6m/s2 along the x-axis and 8m/s2 along the y-axis. Its distance from the origin after 4 seconds will be 

(1) 56 m

(2) 64 m

(3) 80 m

(4) 128 m

Subtopic:  Uniformly Accelerated Motion |
 75%
From NCERT
PMT - 1999
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A car moving with a velocity of 10 m/s can be stopped by the application of a constant force F in a distance of 20 m. If the velocity of the car is 30 m/s, it can be stopped by this force in 

(1) 203m

(2) 20 m

(3) 60 m

(4) 180 m

Subtopic:  Uniformly Accelerated Motion |
 72%
From NCERT
PMT - 1999
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The displacement of a particle is given by y=a+bt+ct2dt4. The initial velocity and acceleration are, respectively:

1. \(\mathrm{b}, ~\mathrm{-4d}\) 2. \(\mathrm{-b},~ \mathrm{2c}\)
3. \(\mathrm{b}, ~\mathrm{2c}\) 4. \(\mathrm{2c}, ~\mathrm{-2d}\)
Subtopic:  Non Uniform Acceleration |
 81%
From NCERT
PMT - 1999
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A car moving with a speed of 40 km/h can be stopped by applying brakes for atleast 2 m. If the same car is moving with a speed of 80 km/h, what is the minimum stopping distance ?

(1) 8 m

(2) 2 m

(3) 4 m

(4) 6 m

Subtopic:  Uniformly Accelerated Motion |
 76%
From NCERT
PMT - 1998
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