The position of a body with acceleration \(a\) is given by \(x= Ka^{m}t^{n}\) (assume \(t\) to be time). The values of \(m\) and \(n\) will be:
1. \(m=1,~n=1\)
2. \(m=1,~n=2\)
3. \(m=2,~n=1\)
4. \(m=2,~n=2\)

Subtopic:  Dimensions |
 76%
From NCERT
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The period of oscillation of a simple pendulum is given by T=2πlg where l is about 100 cm and is known to have 1 mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stopwatch of least count 0.1 s. The percentage error in g is:

1. 0.1%

2. 1%

3. 0.2%

4. 0.8%

Subtopic:  Errors |
 50%
From NCERT
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The percentage errors in the measurement of mass and speed are \(2\%\) and \(3\%\) respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed:
1. \(11\%\)
2. \(8\%\)
3. \(5\%\)
4. \(1\%\)

Subtopic:  Errors |
 85%
From NCERT
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What is the number of significant figures in \(0.310\times 10^{3}\)?
1. \(2\)
2. \(3\)
3. \(4\)
4. \(6\)

Subtopic:  Significant Figures |
 78%
From NCERT
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The decimal equivalent of \(\frac{1}{20} \) up to three significant figures is:

1. \(0.0500\) 2. \(0.05000\)
3. \(0.0050\) 4. \(5.0 \times 10^{-2}\)
Subtopic:  Significant Figures |
 68%
From NCERT
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The periods of oscillation of a simple pendulum in an experiment are recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s, and 2.80 s respectively. The average absolute error will be:

1. 0.1 s

2. 0.11 s

3. 0.01 s

4. 1.0 s

Subtopic:  Errors |
 61%
From NCERT
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The length of a cylinder is measured with a meter rod having the least count of 0.1 cm. Its diameter is measured with vernier callipers having the least count of 0.01 cm. Given that the length is 5.0 cm and the radius is 2.0 cm. The percentage error in the calculated value of the volume will be

1. 1%

2. 2%

3. 3%

4. 4%

Subtopic:  Errors |
 63%
From NCERT
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In an experiment, the following observations were recorded: initial length L = 2.820 m, mass M = 3.00 kg, change in length l = 0.087 cm, diameter D = 0.041 cm. Taking g = 9.81 m/s2 and using the formula, Y = 4MgLπD2l, the maximum permissible error in Y will be:

1. 7.96%

2. 4.56%

3. 6.50%

4. 8.42%

Subtopic:  Errors |
From NCERT
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A physical quantity P is given by P = A3B12C4D32. The quantity which contributes the maximum percentage error in P is:
1. A
2. B
3. C
4. D

Subtopic:  Errors |
 67%
From NCERT
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The number of significant figures in the numbers \(25.12,\) \(2009,\) \(4.156\) and \(1.217\times 10^{-4}\) is:
1. \(1\)
2. \(2\)
3. \(3\)
4. \(4\)

Subtopic:  Significant Figures |
 92%
From NCERT
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