${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2\mathrm{Cl}+{\mathrm{H}}_3{\mathrm{PO}}_2+{\mathrm{H}}_2\mathrm{O}$:

The product from the above reaction would be -

$1.{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{NC}$

$2. {\mathrm{C}}_6{\mathrm{H}}_6{\mathrm{CH}}_3$

$3.{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CN}$

$4. {\mathrm{C}}_6{\mathrm{H}}_6$

 

The primary amine is -

1. ${\left({\mathrm{CH}}_3\right)}_2{\mathrm{CHNH}}_2$

2. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{NH}-{\mathrm{CH}}_3$

3. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{N}{\left({\mathrm{CH}}_3\right)}_2$

4. None of the above

Which of the following is a secondary amine is -

$1. {\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_2{\mathrm{NH}}_2$
$2. {\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3$
$3. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NHCH}}_3$
$4. {\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2$

The tertiary amine is-

$1. {\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3$
$2. {\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2$
$3. \mathrm{m}-{\mathrm{BrC}}_6{\mathrm{H}}_4{\mathrm{NH}}_2$
$4. \mathrm{None} \mathrm{of} \mathrm{these}$

The chemical test used to distinguish between aniline and benzylamine is-

1. Nitrous acid.

2. Reduction Reaction

3. Hinsberg reagent

4. None of above

The chemical test used to distinguish between aniline and N-methyl aniline is-

1. Carbylamine test 

2. Hoffmann bromamide reaction

3. Acetylation

4. None of above

The chemical test used to distinguish between methylamine and dimethylamine is-

1. Hoffmann bromamide reaction

2. Hinsberg's reagent 

3. Carbylamine test

4. Both 2 and 3

X, Y, and Z in the above sequence are -

1. X= Fe/HCl, Y= ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, and Z = ${\mathrm{H}}_2\mathrm{O}$/ warm

2. X= ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, Y= Fe/HCl, and Z = ${\mathrm{H}}_2\mathrm{O}$/ warm

3.  X= $\mathrm{HBr}/ \mathrm{hv}$, Y= Fe/HCl, and Z = ${\mathrm{H}}_3{\mathrm{PO}}_2$

4. X = $\mathrm{HBr}/ \mathrm{hv}$ Y = ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, and Z = ${\mathrm{H}}_3{\mathrm{PO}}_2$

X, and Y in the following sequence are :

1.	X =  Br2 / CS2 , and Y =
2.	X =  Br2 / H2O  and Y =
3.	X =  Br2 / CS2 , and Y =
4.	X =  Br2 / H2O  and Y =

Benzyl chloride $\stackrel{\mathrm{KCN}}{\to }$ X $\stackrel{LiAl{H}_4}{\to }$ Y

The product X and Y are -

1. 2-Phenylethanenitrile and Benzoic acid

2. Benzonitrile and Benzoic acid

3. 2-Phenylethanenitrile and 2-Phenylethanamine

4. Benzonitrile and 2-Phenylethanamine