A balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen is:

1. 4NH3 + \(\underset{\text{From air}}{5O_2} \)   \(\xrightarrow[\text{500 K; 9 bar}]{\text{Pt / Rh gauge catalyst}}\)   4NO + 6H2O
2. 3NH4 + \(\underset{\text{From air}}{5O_2} \)  \(\xrightarrow[\text{500 K; 9 bar}]{\text{Pt / Rh gauge catalyst}}\)  3NO + 6H2O
3. 4NH3 + \(\underset{\text{From air}}{5O_2} \)  \(\xrightarrow[\text{cold}]{\text{no catalyst}}\)  4NO + 6H2O
4. 3NH4 + \(\underset{\text{From air}}{5O_2} \)  \(\xrightarrow[\text{cold}]{\text{no catalyst}}\)  3NO + 6H2O

Subtopic:  Group 15 - Preparation, Properties & Uses |
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The correct structure of pyrophosphoric acid is:

1. 2.
3. 4.
Subtopic:  Group 15 - Preparation, Properties & Uses |
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PH3 forms bubbles when passed slowly through water but NH3 gets dissolved in water, because: 

1. NH3 forms an H-bond with water, so it is soluble but PH3 does not form an H-bond.
2. NH3 does not form an H-bond with water, so it is soluble but PH3 does form an H-bond.
3. NH3 and PHboth form H-bond with water. 
4. NH3 and PHboth do not form H-bond with water.

Subtopic:  Group 15 - Preparation, Properties & Uses |
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All the five bonds of PCl5 are not equivalent because:

1. Equatorial bond pairs suffer more repulsion as compared to axial bond pairs.
2. Axial bond pairs suffer more repulsion as compared to equatorial bond pairs.
3. Axial and equatorial bond pairs suffer more repulsion.
4. None of the above.

Subtopic:  Group 15 - Preparation, Properties & Uses |
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Nitrogen dioxide is paramagnetic in a gaseous state but diamagnetic in solid because:

1. NO2 exists as a dimer in a gaseous as well as solid state.
2. NO2 exists as a monomer in a gaseous as well as solid state.
3. NO2 exists as a dimer in a gaseous state and it becomes a monomer in solid state.
4. NO2 exists as a monomer in a gaseous state and it becomes dimerized in solid state.

Subtopic:  Group 15 - Preparation, Properties & Uses |
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The correct statement regarding the bond angle of H2O and H2S is:

1. Both have the same bond angle.

2. Bond angle of H2O is larger than that of H2S

3. Bond angle of H2O is smaller than that of H2

4. None of the above.

Subtopic:  Group 16 - Preparation, Properties & Uses |
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An amorphous solid“A” burns in the air to form a gas “B” which turns lime water milky. The gas is also produced as a by-product during the roasting of sulphide ore. This gas decolourises acidified aqueous KMnO4 solution and reduces Fe3+ to Fe2+. The solid "A" and the gas "B" are:

1. 'A' = S8: ‘B' = SO2

2. 'A' = S8: ‘B' = SO3

3. 'A' = S10: ‘B' = SO2

4. Not predictable

Subtopic:  Group 16 - Preparation, Properties & Uses |
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The disproportionation reaction of H3PO3 is as follows:

H3PO3  X + Y

 X and Y in the above reaction are:

1. H3PO2, HPO2  

2. H3PO4, PH3

3. H2PO6, PO3

4. None of the above.

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The catalyst that is used in the contact process is:

1. Fe2O3 2. Al2O3
3. V2O5 4. SO3
Subtopic:  Group 16 - Preparation, Properties & Uses |
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The chemical formula of oleum is - 

1. H2S2O8 2. H2S2O7
3. H3S2O6 4. H2SO5
Subtopic:  Group 16 - Preparation, Properties & Uses |
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