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Q. No.Given below are two statements:
Assertion (A):
When PCl5 is heated then PCl3 and Cl2 are obtained as products.
Reason (R):
PCl5 gives POCl3 with water.
1.
Both (A) and (R) are true and (R) is the correct explanation of (A).
2.
Both (A) and (R) are true but (R) is not the correct explanation of (A).
3.
(A) is true but (R) is false.
4.
(A) is false but (R) is true.
Subtopic: Group 15 - Preparation, Properties & Uses |
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Consider the following reaction:
PCl5 + H2O → A + 2HCl
The product A is -
1. H3PO2
2. H3PO4
3. POCl3
4. None of the above
Subtopic: Group 15 - Preparation, Properties & Uses |
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Subtopic: Group 15 - Preparation, Properties & Uses |
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Consider the following equation,
H3PO3 \(\xrightarrow[]{\Delta }\) X + Y
The products X and Y are respectively -
1. H3PO2 ; PH3
2. H3PO4 ; PH3
3. H3PO4 ; H3PO2
4. None of the above
H3PO3 \(\xrightarrow[]{\Delta }\) X + Y
The products X and Y are respectively -
1. H3PO2 ; PH3
2. H3PO4 ; PH3
3. H3PO4 ; H3PO2
4. None of the above
Subtopic: Group 16 - Preparation, Properties & Uses |
65%
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The important source(s) of sulphur among the following is/are:
1. Gypsum
2. Epsom salt
3. Galena
4. All of the above
1. Gypsum
2. Epsom salt
3. Galena
4. All of the above
Subtopic: Group 16 - Preparation, Properties & Uses |
85%
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What is the correct order of thermal stability of the hydrides of Group 16 elements?
1. H2O < H2S < H2Se < H2Te
2. H2O > H2S > H2Se > H2Te
3. H2O > H2S < H2Se < H2Te
4. H2O > H2S > H2Se < H2Te
1. H2O < H2S < H2Se < H2Te
2. H2O > H2S > H2Se > H2Te
3. H2O > H2S < H2Se < H2Te
4. H2O > H2S > H2Se < H2Te
Subtopic: Group 16 - Preparation, Properties & Uses |
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H2O is a liquid whereas H2S is a gas because of:
1. Stronger van der Waals force in H2O
2. Stronger hydrogen bonding in H2O
3. Stronger ion-dipole interaction in H2O
4. High dissociation constant of H2O
1. Stronger van der Waals force in H2O
2. Stronger hydrogen bonding in H2O
3. Stronger ion-dipole interaction in H2O
4. High dissociation constant of H2O
Subtopic: Group 16 - Preparation, Properties & Uses |
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Subtopic: Group 16 - Preparation, Properties & Uses |
84%
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Consider the following reactions,
a. C2H4 + 3O2→ X + 2H2O
b. 4Al+ 3O2 → Z
X and Z are respectively-
1. X = 1 mole of CO2; Z = 4 moles of Al2O3
2. X = 2 moles of ethanoic acid; Z = 2 moles of AlO3
3. X = 2 moles of CO2; Z = 2 moles of Al2O3
4. X = 2 moles of ethanoic acid; Z = 4 moles of Al2O3
Subtopic: Group 16 - Preparation, Properties & Uses |
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| Assertion (A): | O3 acts as a powerful oxidizing agent. |
| Reason (R): | Ozone decomposes readily on heating to give a molecule of oxygen and nascent oxygen. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Group 16 - Preparation, Properties & Uses |
86%
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NEET 2023 - Target Batch - Aryan Raj Singh
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