Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below: 
 
Then the species undergoing disproportionation is:-

1. \(\text{BrO}^-_3\) 2. \(\text{BrO}^-_4\)
3. \(\text{Br}_2\) 4. \(\text{HBrO}\)

Subtopic:  Electrode & Electrode Potential |
 60%
From NCERT
NEET - 2018
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NEET 2023 - Target Batch - Aryan Raj Singh
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In the electrochemical cell:

Zn|ZnSO4(0.01 M) || CuSO4(1.0M),Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 is changed to 0.01 M, the emf changes to E2. The relationship between E1 and E2 is : 
( Given, RT= 0.059)

1. E1 = E2

2. E1 < E2

3. E1 > E2

4. E2 = 0 ≠ E1

Subtopic:  Electrode & Electrode Potential | Nernst Equation |
 68%
From NCERT
NEET - 2017
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
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To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh