An organic compound contains 69% carbon, and 4.8% hydrogen, the remainder being
oxygen. The masses of carbon dioxide, and water produced when 0.20 g of this substance is subjected to complete combustion would be respectively -

1. 0.506 g , 0.0864 g

2. 0.906 g , 0.0864 g

3. 0.0506 g , 0.864 g

4. 0.0864 g, 0.506 g

In the organic compound${\mathrm{CH}}_2=\mathrm{CH}–{\mathrm{CH}}_2–{\mathrm{CH}}_2–\mathrm{C}\equiv \mathrm{CH}$, the pair of hydridized orbitals involved in the formation of C₂ – C₃ bond is-
1. sp – ${\mathrm{sp}}^2$ 

2. sp – ${\mathrm{sp}}^3$

3. ${\mathrm{sp}}^2$ – ${\mathrm{sp}}^3$

4. ${\mathrm{sp}}^3$ – ${\mathrm{sp}}^3$ 

Any type of chromatography shares which of the following characteristic?

1. Use of molecules that are soluble in water.

2. Use of inert carrier gas.

3. Calculation of R_f value for the molecule separated.

4. Use of a mobile and a stationary phase.

The number of σ and π bonds in the molecule $C_6{H}_6$ are -

The number of σ and π bonds in the molecule $C_6{H}_{12}$ are-

1. 7 = (${\sigma }_{C-C})$ , 11 =  $\left({\sigma }_{C-H}\right)$, and 0= π 

2. 6 = (${\sigma }_{C-C})$ , 12 =  $\left({\sigma }_{C-H}\right)$, and 0= π 

3. 12 = (${\sigma }_{C-C})$ , 6 =  $\left({\sigma }_{C-H}\right)$, and 1= π 

4. 5 = (${\sigma }_{C-C})$ , 13 =  $\left({\sigma }_{C-H}\right)$, and 1= π 

The number of σ and π bonds in the molecule ${\mathrm{CH}}_2{\mathrm{Cl}}_2$ are -

1.  2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

2. 2 = (${\sigma }_{C-Cl})$ , 2= $\left({\sigma }_{C-H}\right)$ , and 0= π

3. 2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

4. 2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

Chlorine atom can be classified as -

$\stackrel{1}{C}{H}_2$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are - 

The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -$\stackrel{1}{\mathrm{ \; C}}{H}_3-\stackrel{}{C}$ $2H=\stackrel{3}{C}{H}_2$

The correct hybridization states of carbon atoms in the following compound are - $\stackrel{1}{\mathrm{ \; \; C}}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv N$