A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 mL of 0.5 M H2SO4. The residual acid required 60 mL of 0.5 M solution of NaOH for neutralization. The percentage composition of nitrogen in the compound is:

1. 52%

2. 61%

3. 56 %

4. 54 %

Subtopic:  Quantitative Analysis of Organic Compounds |
 70%
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In the organic compound CH2=CHCH2CH2CCH, the pair of hydridized orbitals involved in the formation of C2 – C3 bond is-
1. sp – sp2 

2. sp – sp3

3. sp2 – sp3

4. sp3 – sp3 

Subtopic:  Hybridisation & Structure of Carbon Compounds |
 82%
From NCERT
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The correct statement regarding ambident nucleophiles is:

1. Nucleophiles have equal atomic weight.

2. Nucleophiles have only five electrons.

3. Nucleophiles have two nucleophilic sites.

4. Nucleophiles have two electrophilic sites.

Subtopic:  Nucleophile & Electrophile |
 88%
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Any type of chromatography shares which of the following characteristic?

1. Use of molecules that are soluble in water.

2. Use of inert carrier gas.

3. Calculation of Rf value for the molecule separated.

4. Use of a mobile and a stationary phase.

Subtopic:  Quantitative Analysis of Organic Compounds |
 64%
From NCERT
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The number of σ and π bonds in the molecule C6H6 are -

1. 6 C – C sigma ( σ C - C )  bonds, 5 C–H sigma ( ( σ C - H )  bonds, and 3 C=C pi ( π C - C ) 
2. 6 C – C sigma ( σ C - C )  bonds, 5 C–H sigma ( ( σ C - H )  bonds, and 2 C=C pi ( π C - C ) 
3. 6 C – C sigma ( σ C - C )  bonds, 6 C–H sigma ( ( σ C - H )  bonds, and 3 C=C pi ( π C - C ) 
4. 6 C – C sigma ( σ C - C )  bonds, 6 C–H sigma ( ( σ C - H )  bonds, and 2 C=C pi ( π C - C ) 

Subtopic:  Hybridisation & Structure of Carbon Compounds |
 88%
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The number of σ and π bonds in the molecule C6H12 are-

1. 7 = (σC-C) , 11 =  (σC-H), and 0= π 

2. 6 = (σC-C) , 12 =  (σC-H), and 0= π 

3. 12 = (σC-C) , 6 =  (σC-H), and 1= π 

4. 5 = (σC-C) , 13 =  (σC-H), and 1= π 

Subtopic:  Hybridisation & Structure of Carbon Compounds |
 63%
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The correct IUPAC name is -

1. 2,2-Dimethylpentane 

2. 2-Dimethylpentane

3. 1-Dimethylpentane

4. 2,2-Dimethylethane

Subtopic:  Nomenclature |
 88%
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The correct IUPAC name of the following structure is

1. 2,4,7-Trimethyloctane

2. 2,5,7-Trimethyloctane

3. 2,3,7-Trimethyloctane

4. All of the above

Subtopic:  Nomenclature |
 87%
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The  IUPAC name of the following molecule is -

 

1. 2-Chloro-4-methylpentane

2. 4-Chloro-2-methylpentane

3. 4-Chloro-4-methylpentane

4. 2-Chloro-2-methylpentane

 

Subtopic:  Nomenclature |
 85%
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C1H2 =C2=O

The correct hybridization states of carbon atoms in the above compound are - 

1. C1= sp , C2= sp3 2. C1= sp, C2= sp
3. C1= sp, C2= sp 4. C1= sp , C2= sp2
Subtopic:  Hybridisation & Structure of Carbon Compounds |
 91%
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