The correct statements among I to III regarding group 13 element oxides are:
(I) Boron trioxide or diboron trioxide is acidic.
(II) Oxides of aluminium and gallium are amphoteric.
(III) Oxides of indium and thallium are basic.
1. (I) and (II) only
2. (I) and (III) only
3. (II) and (III) only
4. (I), (II), and (III) only
C60, an allotrope of carbon contains :
1. 16 hexagons and 16 pentagons.
2. 12 hexagons and 20 pentagons.
3. 18 hexagons and 14 pentagons.
4. 20 hexagons and 12 pentagons.
Which of the following explains why boron is unable to form the BF₆³⁻ ion?
1. Non-availability of s orbitals
2. Non-availability of d orbitals
3. Non-availability of f orbitals
4. None of the above
Consider the following statements
| (i). | Carbon form the most acidic dioxide among the oxide of group 14. |
| (ii). | Pb mostly found in the +2 oxidation state. |
| (iii). | Only silicon used as a semiconductor. |
Identify the correct statement(s):
1. Only iii
2. i, ii
3. ii, iii
4. Only ii
Diamond is covalent, yet it has a high melting point, due to:
| 1. | A hexagonal planar structure |
| 2. | Three-dimensional network involving strong C—C bonds |
| 3. | C-C double bond |
| 4. | Octahedral arrangement of carbon atoms |
In view of the signs of for the following reactions:
The oxidation states more characteristic for lead and tin are respectively:
1. For lead +2, for tin +2
2. For lead +4, for tin +4
3. For lead +2, for tin +4
4. For lead +4, for tin +2
Which of the following explains why diamond is extremely hard while graphite is soft, even though both are made of carbon atoms?
| 1. | Diamond has carbon-carbon double bond while graphite has carbon-carbon single bond |
| 2. | Diamond is ionic whereas graphite is covalent |
| 3. | Diamond has a strong covalent bond with regular tetrahedron pattern |
| 4. | Certain atoms in diamond are smaller in size |
In the borax bead test, the coloured bead is formed due to the formation of:
1. Orthoborate
2. Metaborate
3. Double oxide
4. Tetraborate
Match the species in Column-I with their corresponding hybridisation in Column-II:
| Column-I (Species) | Column-II (Hybridisation) | ||
| A. | Boron in | i. | sp2 |
| B. | Aluminium in | ii. | sp3 |
| C. | Carbon in Buckminsterfullerene | iii. | sp3d2 |
| D. | Germanium in |
Codes:
| A | B | C | D | |
| 1. | ii | iii | i | iii |
| 2. | i | i | iii | ii |
| 3. | iii | ii | ii | i |
| 4. | i | iii | ii | iii |
Me3SiCl is used during polymerization of organ silicones because
| a. | Chain length of organic silicone polymers can be controlled by adding |
| b. | blocks the end terminal of silicone polymer. |
| c. | improves the quality and yield of the polymer. |
| d. | acts as a catalyst during polymerization. |
Choose the correct option:
| 1. | (a, b) | 2. | (b, c) |
| 3. | (c, d) | 4. | (a, d) |