The species doesn't have unpaired electrons is:

1. ${\mathrm{N}}_2^{+}$

2. ${\mathrm{O}}_2$

3. ${\mathrm{O}}_2^{2-}$

4. ${\mathrm{B}}_2$

Among the following, the correct order of energies of molecular orbitals of N₂ is-

1. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)<\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)<(\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

2. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)>\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)>(\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

3. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)<\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

4. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)>\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)<(\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

From the perspective of molecular orbital theory, which statement is false?

1. ${\mathrm{Be}}_2$ is not a stable molecule.

2. ${\mathrm{He}}_2$ is not stable but ${\mathrm{He}}_2^{+}$ is expected to exist.

3. Bond strength of ${\mathrm{N}}_2$ is maximum amongst the homonuclear diatomic molecules belonging to the second period.

4. The order of energies of molecular orbitals in ${\mathrm{N}}_2$ molecule is: 

${\mathrm{\sigma }}_{2\mathrm{s}}<{\mathrm{\sigma }}_{2\mathrm{s}}^{*}<{\mathrm{\sigma }}_{2{\mathrm{p}}_{\mathrm{z}}}<({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}}\approx {\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{y}}})$
$<({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}}^{*}\approx {\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{y}}}^{*})<{\mathrm{\sigma }}_{2{\mathrm{p}}_{\mathrm{z}}}^{*}$

What is the correct sequence of bond order for the specified species?

1. ${\mathrm{O}}_2^{-}$ $>$ ${\mathrm{O}}_2$ $>$ ${\mathrm{O}}_2^{+}$

2. ${\mathrm{O}}_2^{-}$ $<$ ${\mathrm{O}}_2$ $<$ ${\mathrm{O}}_2^{+}$

3. ${\mathrm{O}}_2^{-}$ $>$ ${\mathrm{O}}_2$ $<$ ${\mathrm{O}}_2^{+}$

4. ${\mathrm{O}}_2^{-}$ $<$ ${\mathrm{O}}_2$ $>$ ${\mathrm{O}}_2^{+}$

Match the species in Column I with the bond order in Column II.

Codes

Which of the following have identical bond order?

(a) ${\mathrm{CN}}^{-}$

(b) ${\mathrm{NO}}^{+}$

(c) ${\mathrm{O}}_2^{-}$

(d) ${\mathrm{O}}_2^{2-}$

Choose the correct option

1. (a), (b)

2. (b), (c)

3. (c), (d)

4. (b), (d)

Diamagnetic species are those which contain no unpaired electrons. Among the following, diamagnetic species are

(a) ${\mathrm{N}}_2$

(b) ${\mathrm{N}}_2^{2-}$

(c) ${\mathrm{O}}_2$

(d) ${\mathrm{O}}_2^{2-}$

Choose the correct option

Species have same bond order are

(a) ${\mathrm{N}}_2$

(b) ${\mathrm{N}}_2^{-}$

(c) ${\mathrm{F}}_2^{+}$

(d) ${\mathrm{O}}_2^{-}$

Choose the correct option

1. (a), (d)

2. (b), (c)

3. (c), (d)

4. (b), (d)