The formation of oxide ion O2-(g), from oxygen atom, requires first an exothermic and then an endothermic step as shown below

O(g)+e-O-(g); H=-141 kJ mol-1
O-(g)+e-O2(g); H=+780 kJ mol-1

Thus, the process of formation of O2- in the gas phase is unfavourable even though O2- is isoelectronic with neon. It is due to the fact that

1. Oxygen is more electronegative
2. Addition of electron in oxygen results in a larger size of the ion
3. Electron repulsion outweighs the stability gained by achieving noble gas configuration
4. O- ion has comparatively smaller size than oxygen atom

Subtopic:  Electron Affinity (EA) |
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The outermost electronic configuration of the last element of the p-block in the 6th period is represented by:

1. 7s27p6

2. 5f146d107s27p0

3. 4f145d106s26p6

4. 4f145d106s26p4

Subtopic:  Modern Periodic Table & Periodicity |
 78%
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Among the following elements whose atomic numbers are given below, which cannot be accommodated in the present set up of the long periodic table?

1. 107 2. 118
3. 126 4. 102
Subtopic:  Modern Periodic Table & Periodicity |
 88%
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The elements with atomic numbers 35, 53, and 85 are:

1. Noble gases 2. Halogens
3. Heavy metals 4. Light metals
Subtopic:  Modern Periodic Table & Periodicity |
 83%
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Electronic configuration of four elements A, B, C and D are given below : 

A. 1s22s22p6

B. 1s22s22p4

C. 1s22s22p63s1

D. 1s22s22p5

The correct order of increasing tendency to gain electron is : 

1. A < C < B < D 2. A < B < C < D
3. D < B < C < A 4. D < A < B < C
Subtopic:  Electron Affinity (EA) |
 54%
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Match the correct atomic radius with the corresponding element.

Element

Atomic radius (pm)

A. Be

i. 74

B. C

ii. 85

C. O

iii. 112

D. B

iv. 77

E. N

v. 66

Codes

Options:  A   B   C   D   E 
1.   i  ii  iii  iv  v
2.  iii   iv  v   ii  i
3.  iv  ii  iii   i  v
4.  v  ii    i   iii   iv

Subtopic:  Atomic Size |
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Match the correct ionization enthalpies and electron gain enthalpies of the following elements.

Elements

H1

H2

egH

(i)

Most reactive non-metal

A.

419

3051

-48

(ii)

Most reactive metal

B.

1681

3374

-328

(iii)

Least reactive element

C.

738

1451

-40

(iv)

Metal forming binary halide

D.

2372

5251

+48

Codes

A B C D
1. ii i iv iii
2. i ii iii iv
3. i iv iii ii
4. iv i iii ii
Subtopic:  Ionization Energy (IE) | Electron Affinity (EA) |
 66%
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Electronic configuration of some elements is given in Column I and their electron gain enthalpies are given in Column II. Match the electronic configuration with electron gain enthalpy.

Column I

(Electron configuration)

Column II

(Electron gain enthalpy/kJ mol-1)

A. 1s22s22p6

1. -53

B. 1s22s22p63s1

2. -328

C. 1s22s22p5

3. -141

D. 1s22s22p4

4. +48

Codes

Options:  A   B   C   D 
1.  4 1 2 3
2. 1 2 3 5
3. 1 4 3 2
4. 4 1 3 2

Subtopic:  Electron Affinity (EA) |
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Given below are two statements: 

Assertion (A): Generally, ionisation enthalpy increases from left to right in a period.
Reason (R): When successive electrons are added to the orbitals in the same principal quantum level, the shielding effect of inner core of electrons does not increase very much to compensate for the increased attraction of the electron to the nucleus.

1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. (A) is false but (R) is true.

Subtopic:  Ionization Energy (IE) | Electron Affinity (EA) |
 75%
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Given below are two statements: 

Assertion (A): Boron has a smaller first ionisation enthalpy than beryllium.
Reason (R): The penetration of 2s electron to the nucleus is more than the 2p electron hence 2p electron is more shielded by the inner core of electrons than the 2s electrons.

1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. (A) is false but (R) is true.

Subtopic:  Ionization Energy (IE) |
 76%
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