The wave number of a light whose time period is 2.0 × 10^–10 s would be:

1. 16.66 m^-1

2. 1.66 m^-1

3. 32.34 m^-1

4. 12.34 m^-1

If the diameter of a carbon atom is 0.15 nm, the number of carbon atoms that can be placed side by side in a straight line across the length of the scale of length 20 cm long will be:$\mathrm{}$

Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm.

The frequency (ν) and wave number of this yellow light would be, respectively:

1. 517 x 10¹⁴ s^-1 , 172 x 10⁶ m^-1

2. 6.17 x 10¹⁴ s^-1 , 1.72 x 10⁶ m^-1

3. 4.17 x 10¹⁴ s^-1 , 2.72 x 10⁶ m^-1

4. 5.17 x 10¹⁴ s^-1 , 1.72 x 10⁶ m^-1

2 ×10⁸ atoms of carbon are arranged side by side. The radius of a carbon atom if the length of this arrangement is 2.4 cm would be 

1. 7.0 x 10^-11 m

2. 5.0 x 10^-11 m

3. 8.0 x 10^-11 m

4. 6.0 x 10^-11 m

The diameter of a zinc atom is 2.6 Å. If zinc atoms are arranged side by side lengthwise, number of atoms present in a length of 1.6 cm would be:

A certain particle carries 2.5 × 10^–16 C of static electric charge. The number of electrons present in it would be:

In Rutherford's experiment, generally, the thin foil of heavy atoms like gold, platinum, etc. have been used to be bombarded by the α-particles.

 If the thin foil of light atoms like aluminum etc. is used in Rutherford’s experiment, the difference that would be observed from the above results is :

1. The same results will be observed.

2. More deflection would be observed.

3. There will not be enough deflection.

4. None of the above.

Symbols ${}_{35}{}^{79}\mathrm{Br}$ and ${}^{79}Br$ can be written,
whereas symbols ${}_{79}{}^{35}\mathrm{Br}$ and ${}^{35}Br$ are not acceptable because:

The atomic number of elements whose outermost electronic configuration are represented by 3s¹ and 2p⁵ respectively, is: