- 1(current)
Q. No.When \(1 \text{ dm}^3\) of \(\text{CO}_2\) gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes \(1.4 \text{ dm}^3\). The composition of the gaseous mixture at STP is :
| 1. | \(0.6 \text{ dm}^3\) of \(\text{CO},\) \(0.8 \text{ dm}^3\) of \(\text{CO}_2\) |
| 2. | \(0.8 \text{ dm}^3\) of \(\text{CO},\) \(0.8 \text{ dm}^3\) of \(\text{CO}_2\) |
| 3. | \(0.8 \text{ dm}^3\) of \(\text{CO},\) \(0.6 \text{ dm}^3\) of \(\text{CO}_2\) |
| 4. | \(0.6 \text{ dm}^3\) of \(\text{CO},\) \(0.4 \text{ dm}^3\) of \(\text{CO}_2\) |
Subtopic: Moles, Atoms & Electrons | Concentration Based Problem |
Level 3: 35%-60%
NEET - 2026
Please attempt this question first.
Hints
Please attempt this question first.
How much glucose is needed to prepare 250 mL of a 1/20 M (M/20) glucose solution?
(Molar mass of glucose: 180 g/mol)
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
(Molar mass of glucose: 180 g/mol)
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
Subtopic: Concentration Based Problem |
80%
Level 1: 80%+
NEET - 2024
Hints
What is the molality of a 1 M solution of compound X having density 1.25 g mL⁻¹ and molar mass 85 g mol⁻¹?
1. 0.705 m2. 1.208 m
3. 1.165 m
4. 0.858 m
Subtopic: Concentration Based Problem |
69%
Level 2: 60%+
NEET - 2023
Hints
An aqueous solution of NaOH has a molarity of 2 M and a density of 1.28 g cm⁻³.
Calculate the molality of the solution:
[Given: Molecular mass of NaOH = 40 g mol-1]
| 1. | 1.20 m | 2. | 1.56 m |
| 3. | 1.67 m | 4. | 1.32 m |
Subtopic: Concentration Based Problem |
74%
Level 2: 60%+
NEET - 2019
Hints
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- 1(current)
Q. No.
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