Which one of the following can be explained as the basis of Mendel's Law of dominance?
A: Out of one pair of factors, one is dominant and the other is recessive.
B: Alleles do not show any expression and both the characters appear as such in F2 generation.
C: Factors occur in pairs in normal diploid plants.
D: The discrete unit controlling a particular character is called factor.
E: The expression of only one of the parental characters is found in a monohybrid cross. 

Choose the correct answer from the options given below:
1. A, C, D and E only
2. B, C and D only
3. A, B, C, D and E
4. A, B and C only

Subtopic:  Monohybrid Cross: 1 |
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A pink flowered Snapdragon plant was crossed with red flowered Snapdragon plant. What type of phenotype/s is/are expected in the progeny?
1. Red flowered as well as pink flowered plants
2. Only pink flowered plants
3. Red, Pink as well as white flowered plants
4. Only red flowered plants 
Subtopic:  Law of Segregation | Dominance Deviation from Mendel: 1 |
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In a plant, black seed color (BB/Bb) is dominant over white seed color (bb). In order to find out the genotype of black seed plant, with which of the following genotype will you cross it?
1. bb
2. Bb
3. BB/Bb
4. BB
Subtopic:  Monohybrid Cross: Further Understanding |
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Match List I with List II:
List I List II
A.   Down's syndrome  I.  \(11^{\text {th }}\) chromosome
B.  \(\alpha\) -Thalassemia  II.  \(' \mathrm{X} '\) chromosome
C.  \(\beta\) -Thalassemia  III.  \(21^{\text {st }}\) chromosome
D.  Klinefelter's
syndrome
IV.  \(16^{\text {th }}\) chromosome

Choose the correct answer from the options given below:
1. A-II, B-III,C-IV, D-I 
2. A-III, B-IV,C-I, D-II 
3. A-IV, B-I, C-II, D-III 
4. A-I, B-II, C-III, D-IV
Subtopic:  Mendelian Disorders | Chromosomal Disorders |
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As per \(\mathrm{ABO}\) blood grouping system, the blood group of father is \(\mathrm{B^+}\), mother is \(\mathrm{A^+}\) and child is \(\mathrm{O^+}\). Their respective genotype can be 
A. \(\mathrm{I^{B}i / I^{A}i / ii}\)
B. \(\mathrm{I}^{\mathrm{B}} \mathrm{I}^{\mathrm{B}} / \mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}} / \mathrm{ii}\)
C. \(\mathrm{I^AI^B/iI^A/I^Bi}\)
D. \(\mathrm{I^{A}i / I^{B}i / I^{A}i}\)
E. \(\mathrm{i I^B / i I^A / I^A I^B}\)
Choose the most appropriate answer from the options given below: 
1. B only 
2. C & B only 
3. D & E only 
4. A only 
Subtopic:  Co-dominance |
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ABO blood group is an example of 
1. Incomplete dominance
2. Multiple allele
3. Pleiotropy
4. Linkage
Subtopic:  Co-dominance |
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A cross between tall plants was made resulting in offspring of tall and dwarf plants with ratio 3 : 1. The genotype(s) of both parents are:
1. TT and TT
2. Tt and tt
3. Tt and Tt
4. tt and tt
Subtopic:  Monohybrid Cross: 1 | Monohybrid Cross: Further Understanding |
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Which of the following is NOT an autosomal recessive disorder? 
1. Sickle cell anemia 
2. Phenylketonuria 
3. Haemophilia
4. Thalassemia
Subtopic:  Mendelian Disorders | Mendelian Disorders: Hemophilia |
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Given below are two statements : One is labelled as  Assertion (A) and the other is labelled as Reason (R). 
Assertion (A): In honey bee population, sons do not have fathers but have grandfathers.
Reason (R): Haploidy in drones of honey bee is due to parthenogenesis while fertilisation  results into female bees.
In the light of the above statements, choose the correct answer from the options given below: 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Sex Determination |
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A yellow seeded and violet flowered pea plant was crossed with a green seeded and white flowered pea plant. The progeny showed plants with four different phenotypes. The yellow seeded and violet flowered parent must be:
1. Double homozygous
2. Double heterozygous
3. Homozygous for seed colour and heterozygous for flower colour.
4. Heterozygous for seed colour and homozygous for flower colour.
Subtopic:  Dihybrid Cross Analysis |
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