Assertion: (A) | We cannot see pure DNA fragments in the visible light under microscope. |
Reason: (R) | The DNA fragments separate according to their shape only and are too small to be seen in the gel electrophoresis. |
1. | Both (A) and (R) are True and the (R) is the correct explanation of the (A). |
2. | Both (A) and (R) are True and the (R) is not the correct explanation of the (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
Assertion (A): | One antibiotic resistance gene of vector pBR322 helps in selecting the transformants and the other one in selecting recombinants. |
Reason (R): | The non-recombinants can grow on both antibiotic-rich media while the recombinants grow only on single medium due to insertional inactivation. |
1. | Both (A) and (R) are True and the (R) is the correct explanation of the (A). |
2. | Both (A) and (R) are True and the (R) is not the correct explanation of the (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
1. | Denaturation | - | Phosphodiester bonds break |
2. | Annealing | - | Primers anneal at 5' end of DNA template |
3. | Extension | - | Taq polymerase forms hydrogen bonds between adjacent nucleotides of growing DNA strand |
4. | Extension | - | Thermostable DNA polymerase adds nucleotide to 3' end of primers |
Assertion (A): | Synthetic oligonucleotide polymers are used during annealing in a PCR. |
Reason (R): | The primers bind to the double stranded DNA at their complementary regions. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True and (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
List-I | List-II | ||
(A) | Kanamycin | (I) | Delivers genes into animal cells |
(B) | ClaI | (II) | Selectable marker |
(C) | Disarmed retroviruses | (III) | Restriction site |
(D) | Kanamycin Rgene | (IV) | Antibiotic resistance |
Options: | (A) | (B) | (C) | (D) |
1. | (II) | (III) | (I) | (IV) |
2. | (III) | (I) | (IV) | (II) |
3. | (IV) | (III) | (I) | (II) |
4. | (II) | (IV) | (I) | (III) |
A. | Insertion of recombinant DNA into the host cell. |
B. | Cutting of DNA at specific location by restriction enzyme. |
C. | Isolation of desired DNA fragment. |
D. | Amplification of gene of interest using PCR. |
1. | B, D, A, C | 2. | B, C, D, A |
3. | C, A, B, D | 4. | C, B, D, A |
I: | Plasmid |
II: | Phage DNA |
I. | Non-Transformants will not survive in a medium containing antibiotic A and in a medium containing antibiotic B. |
II. | Recombinant transformants will survive in a medium containing antibiotic B but not in a medium containing antibiotic A. |
III. | Non-recombinant transformants will survive in a medium containing antibiotic A and in a medium containing antibiotic B. |
Assertion (A): | Foreign and vector DNA must be cleaved with the same restriction enzyme when making recombinant DNA. |
Reason (R): | Each restriction enzyme cuts DNA at a specific cleavage site. |
1. | Both (A) and (R) are True and (R) correctly explains (A). |
2. | (A) is True; (R) is False |
3. | (A) is False; (R) is True |
4. | Both (A) and (R) are True but (R) does not correctly explain (A). |
Assertion (A): | In order to force bacteria to take up the plasmid, the bacterial cells must be ‘competent’ to take up DNA. |
Reason (R): | No bacteria have natural competence. |
1. | (A) is True but (R) is False. |
2. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
3. | (A) is False and (R) is True. |
4. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |