H2O2 behave as a bleaching agent because :

Incorrect statement regarding structure of H₂O and H₂O₂ is:

1. In gaseous phase, water molecule has a bent form.

2. Bond angle of water is $109.0°$

3. Hydrogen peroxide has a non-planar structure.

4. The dihedral angle of H₂O₂ in gas phase is 111.5° 

The following reaction is an example of :

\(2 \mathrm{MnO}_4^{-}+6 \mathrm{H}^{+}+5 \mathrm{H}_2 \mathrm{O}_2 \rightarrow 2 \mathrm{Mn}^{2+}+8 \mathrm{H}_2 \mathrm{O}+5 \mathrm{O}_2\)

1. Hydrolysis reaction

2. Redox reaction

3. Disproportionation reaction

4. None of the above

The reaction in which hydrogen peroxide acts as a reducing agent is/are-

1. ${\mathrm{Mn}}^{+2} \hspace{0.17em}+{\mathrm{H}}_2{\mathrm{O}}_2 \to {\mathrm{Mn}}^{+4} +\hspace{0.17em}2{\mathrm{OH}}^{-}$

2. $\mathrm{PbS} +4{\mathrm{H}}_2{\mathrm{O}}_2 \to {\mathrm{PbSO}}_4 +\hspace{0.17em}4{\mathrm{H}}_2\mathrm{O}$

3. ${\mathrm{I}}_2 + {\mathrm{H}}_2{\mathrm{O}}_2 + 2{\mathrm{OH}}^{-} \to 2{\mathrm{I}}^{-} +\hspace{0.17em}2{\mathrm{H}}_2\mathrm{O}\hspace{0.17em}+ {\mathrm{O}}_2$

4. All of the above