The role of an electrolyte in the  preparation of H₂ by electrolytic method is:

1.	It lowers the availability of ions available in the process for the conduction of electricity.
2.	It makes the ions available in the process for conduction of electricity.
3.	It cools down the temperature.
4.	None of the above

The products obtained on the completion of the following reactions (i) and (ii) respectively are :

1. A = CO, and H₂ ; B = Na₂ZnO₂
2. A  = CO₂ ; B = Na₄ZnO₄
3. A = CH₃CH₂CH₂OH ; B=  ZnO
4. None of the above

The consequences of high enthalpy of H–H bond in dihydrogen is /are :

The correct statement about electron-deficient hydride is that it:

The hydrides of carbon (C_nH_{2n + 2}) can act as -

1. Lewis acid.

2. Lewis base.

3. Both 1 and 2

4. None of the above

“Non-stoichiometric hydrides” are :

Metallic hydrides are useful for hydrogen storage because : 

1. Metallic hydrides are oxygen-rich.

2. Metallic hydrides are oxygen-deficient.

3. Metallic hydrides are hydrogen-rich.

4. Metallic hydrides are hydrogen-deficient.

Atomic hydrogen or oxy-hydrogen torch is used for cutting and welding purposes because:

 The correct order of hydrogen bonding among ${\mathrm{NH}}_3$, H2O and HF, is 

1. HF > ${\mathrm{H}}_2\mathrm{O}$ > ${\mathrm{NH}}_3$

2. ${\mathrm{H}}_2\mathrm{O}$ > HF > ${\mathrm{NH}}_3$

3. HF > ${\mathrm{NH}}_3$ > ${\mathrm{H}}_2\mathrm{O}$

4. ${\mathrm{NH}}_3$ > HF > ${\mathrm{H}}_2\mathrm{O}$

CO2  is used as a fire extinguisher because -

1. ${\mathrm{CO}}_2$ has high lattice energy.

2. ${\mathrm{CO}}_2$ will be effective in isolating the burning surface from dihydrogen and dioxygen.

3. ${\mathrm{CO}}_2$ is lighter than dioxygen.

4. ${\mathrm{CO}}_2$ is lighter than dihydrogen.