The large difference between the melting and boiling points of oxygen and sulphur may be explained based on:
1. Atomic size
2. Atomicity
3. Electronegativity
4. Electron gain enthalpy
Subtopic:  Group 16 - Preparation, Properties & Uses |
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Level 3: 35%-60%
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When sodium thiosulphate is reacted with I2 , then the product of sulphur will be:

1. Na2SO3

2. Na2SO4

3. Na2S4O6

4. SO2

Subtopic:  Group 16 - Preparation, Properties & Uses |
Level 3: 35%-60%
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If the boiling point of H2O is 373 K, the boiling point of H2S will be:

1. Greater than 300 K but less than 373 K
2. Less than 300 K
3. More than 373 K
4. Equal to 373 K

Subtopic:  Group 16 - Preparation, Properties & Uses |
Level 3: 35%-60%
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Assertion (A): The \(S-S-S\) bond angle in \(S_8\) molecule is 105°.
Reason (R): \(S_8\) has V-shape.
 
1. Both (A) and (R) are True, and (R) is the correct explanation of (A).
2. Both (A) and (R) are True, but (R) is not the correct explanation of (A).
3. (A) is True, but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Group 16 - Preparation, Properties & Uses |
Level 3: 35%-60%
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Incorrectly matched characteristic is:

1. S8: covalent lattice

2. P4: tetrahedron

3. S52-: zigzag

4. SiO2: Covalent lattice

Subtopic:  Group 16 - Preparation, Properties & Uses |
Level 4: Below 35%
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