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Q. No.Given below are two statements :
Statement I:
Like nitrogen that can form ammonia, arsenic can form arsine.
Statement II:
Antimony cannot form antimony pentoxide.
In the light of the above statements, choose the most appropriate answer from the options given below :
1.
Statement I is correct but Statement II is incorrect
2.
Statement I is incorrect but Statement II is correct
3.
Both Statement I and Statement II are correct
4.
Both Statement I and Statement II are incorrect
Subtopic: Group 15 - Preparation, Properties & Uses |
From NCERT
NEET - 2025
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The large difference between the melting and boiling points of oxygen and sulphur may be explained based on:
1. Atomic size
2. Atomicity
3. Electronegativity
4. Electron gain enthalpy
1. Atomic size
2. Atomicity
3. Electronegativity
4. Electron gain enthalpy
Subtopic: Group 16 - Preparation, Properties & Uses |
From NCERT
JEE
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The correct decreasing order of positive electron gain enthalpy for the following inert gases is:
He, Ne, Kr, Xe
1. He > Ne > Kr > Xe
2. He > Ne > Xe > Kr
3. He > Xe > Ne > Kr
4. Ne > Kr > Xe > He
He, Ne, Kr, Xe
1. He > Ne > Kr > Xe
2. He > Ne > Xe > Kr
3. He > Xe > Ne > Kr
4. Ne > Kr > Xe > He
Subtopic: Group 18 - Preparation, Properties & Uses |
From NCERT
JEE
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Subtopic: Group 15 - Preparation, Properties & Uses |
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| Assertion (A): | Nitrogen is unreactive at room temperature but becomes reactive at elevated temperatures (on heating) or in the presence of catalysts. |
| Reason (R): | In nitrogen molecules, there is extensive delocalization of electrons. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Group 15 - Preparation, Properties & Uses |
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| Assertion (A): | The \(S-S-S\) bond angle in \(S_8\) molecule is 105°. |
| Reason (R): | \(S_8\) has V-shape. |
| 1. | Both (A) and (R) are True, and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True, but (R) is not the correct explanation of (A). |
| 3. | (A) is True, but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Group 16 - Preparation, Properties & Uses |
From NCERT
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| Assertion (A): | Molecular nitrogen is less reactive than molecular oxygen. |
| Reason (R): | The bond length of N2 is shorter than that of oxygen. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False |
| 4. | (A) is False but (R) is True. |
Subtopic: Group 15 - Preparation, Properties & Uses |
From NCERT
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When \(NH_3\) gas is passed through Nessler's reagent, a red-brown solution is obtained. It is due to the formation of
1. Millon's base
2. Potassium mercuric iodide
3. \(HgI_2\)
4. \(K_2HgI_4 + KOH \)
1. Millon's base
2. Potassium mercuric iodide
3. \(HgI_2\)
4. \(K_2HgI_4 + KOH \)
Subtopic: Group 15 - Preparation, Properties & Uses |
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The most acidic oxyacid of phosphorous is
1. \(H_3PO_4 \)
2. \(HPO_3 \)
3. \(H_4P_2O_7 \)
4. \(H_3PO_2 \)
1. \(H_3PO_4 \)
2. \(HPO_3 \)
3. \(H_4P_2O_7 \)
4. \(H_3PO_2 \)
Subtopic: Group 15 - Preparation, Properties & Uses |
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The correct order of acidic strength of HPO3, H3PO4, H3PO3 and H3PO2 is:
\(1. \mathrm{HPO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}\\ 2. \mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{HPO}_{3}\\ 3.\mathrm{HPO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{4}\\ 4.\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H} \mathrm{PO}_{3}\)
\(1. \mathrm{HPO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}\\ 2. \mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{HPO}_{3}\\ 3.\mathrm{HPO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{4}\\ 4.\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H} \mathrm{PO}_{3}\)
Subtopic: Group 15 - Preparation, Properties & Uses |
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