The correct shape and hybridization for XeF4 are:
1. Octahedral, sp3d2
2. Trigonal bipyramidal, sp3d3
3. Planar triangle, sp3d3
4. Square planar, sp3d2
Which of the following is the incorrect statement?
1. PH5 and BiCl5 do not exist
2. pπ - dπ bonds are present in SO2
3. SeF4 and CH4 have the same shape
4. \(\mathrm{I_{3}^{+}}\)
| 1. | BeH2 < CaH2 < BaH2 | 2. | CaH2 < BeH2 < BaH2 |
| 3. | BeH2 < BaH2 < CaH2 | 4. | BaH2 < BeH2 < CaH2 |
| 1. | NO | 2. | CN– |
| 3. | CN+ | 4. | CN |
Mark the correct order of repulsion among the following according to the VSEPR theory.
| 1. | lone pair-lone pair > bond pair-bond pair >lone pair-bond pair |
| 2. | bond pair-bond pair> lone pair-bond pair>lone pair-lone pair |
| 3. | lone pair-bond pair > bond pair-bond pair >lone pair-lone pair |
| 4. | lone pair-lone pair> lone pair-bond pair>bond pair-bond pair |
In which orbital is the pair of electrons located in the provided carbanion, CH3C≡C– ?
1. sp3
2. sp2
3. sp
4. 2p
| 1. | The H-O-H bond angle in H2O is larger than the H-C-H bond angle in CH4 |
| 2. | The H-C-H bond angle in CH4 is larger than the H-N-H bond angle in NH3 |
| 3. | The H-C-H bond angle in CH4, the H-N-H bond angle in NH3 and the H-0-H bond angle in H2O are all greater than 90o |
| 4. | The H-O-H bond angle in H2O is smaller than the H-N-H bond angle in NH3 |
The decreasing order of stability of is:
1.
2.
3.
4.
Which of the following species contains an equal number of and bonds?
1.
2.
3.
4. CH2(CN)2
| 1. | \(\mathrm{CO}_3^{2-}, \mathrm{SO}_3^{2-} \) | 2. | \(\mathrm{ClO}_3^{-}, \mathrm{CO}_3^{2-} \) |
| 3. | \(\mathrm{SO}_3^{2-}, \mathrm{NO}_3^{-} \) | 4. | \(\mathrm{ClO}_3^{-}, \mathrm{SO}_3^{2-}\) |