Why is the Wurtz reaction not preferred for the preparation of alkanes containing an odd number of carbon atoms?

1. Boiling points of alkanes obtained in the mixture are very close
2. Melting points of alkanes obtained in the mixture are very close
3. Lattice energy of alkanes obtained in the mixture are very close
4. None of the above

Subtopic:  Mechanism of Reactions | Chemical Properties |
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The correct sequence for increasing dipole moment is:

1. CCl4 < CHCl3 < CH2Cl2
2. CHCl3 < CH2Cl2 < CCl4
3. CCl4 < CH2Cl2 < CHCl3
4. CH2Cl2 < CCl4 < CHCl3

Subtopic:  Introduction and Physical Properties |
 52%
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A hydrocarbon C5H10 does not react with chlorine in the dark but gives a single monochloro compound C5H9Cl in bright sunlight. Hydrocarbon could be:

1. Benzene 2. Cyclopentane
3. Toluene 4. Hexane
Subtopic:  Mechanism of Reactions | Chemical Properties |
 77%
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The compound with the formula C4H9Br has how many structural isomers?

1. 6 2. 3
3. 5 4. 4
Subtopic:  Isomerism & Chirality |
 57%
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a. CH3Br or CH3I  
b. (CH3)3CCl or CH3Cl
The above-mentioned compounds that react faster in S N2 reaction with OH- from each given pair respectively are:

1. CH3Br, CH3I
2. CH3Br, (CH3)3CCl
3. CH3I, CH3Cl
4. CH3I, (CH3)3CCl

Subtopic:  Chemical Properties |
 74%
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Out of C6H5CH2Cl and C6H5CHClC6H5, the one that gets easily hydrolyzed by aqueous KOH is :

1. C6H5CHClC6H5 

2. C6H5CH2Cl

3. Both react equally

4. None of the above

Subtopic:  Mechanism of Reactions |
 56%
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p-Dichlorobenzene has a higher melting point than those of o- and m-isomers because :

1. More energy is required to break the crystal lattice of m-dichlorobenzene
2. More energy is required to break the crystal lattice of p-dichlorobenzene
3. More energy is required to break the crystal lattice of o-dichlorobenzene
4. None of the above
Subtopic:  Introduction and Physical Properties |
 88%
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Primary alkyl halide C4H9Br(A) reacted with alcoholic KOH to give compound (B). Compound (B) is reacted with HBr to give (C), and it was found that C is an isomer of (A).
(A) with sodium metal, gives compound (D),
C8H18 
which is different from the compound formed when n-butyl bromide is reacted with sodium.
Compound (A) is :

1. 2-Methylpropene

2. Isobutyl bromide

3. 2,5-Dimethylhexane

4. 2-Bromo-2-methylpropane

Subtopic:  Chemical Properties |
 67%
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In the presence of ZnCl2, the substrate used to produce 1-iodobutane from HI is?

1. 1-Butanol 2. Butane
3. Butyne 4. Butanal
Subtopic:  Mechanism of Reactions |
 79%
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The best substrate for the preparation of 1-iodobutane in the presence of NaI/dry acetone is:
1. 1-Chlorobutane 
2. n-Butane
3. Butanol
4. Butyne

Subtopic:  Mechanism of Reactions |
 72%
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