The relative velocity of two adjacent layers of a liquid is \(6~\text{cm/s}\) and the perpendicular distance between layers is \(0.1~\text{mm}.\) The velocity gradient for liquid (in per second) is:
1. \(6\)
2. \(0.6\)
3. \(0.06\)
4. \(600\)
A large open tank with a square hole of side \(0.1\) cm in the wall at a depth of \(0.2\) m from the top is completely filled with a liquid. The rate of flow of liquid (in /s) through the hole will be:
1. | \(1\) | 2. | \(2\) |
3. | \(3\) | 4. | \(4\) |
The property of surface tension of the liquid is due to:
1. | the gravitational force of attraction between the molecules. |
2. | the cohesive forces between the molecules. |
3. | the adhesive force between the molecules. |
4. | the formation of ionic bonds between the molecules. |
If two iron balls when fully immersed in water experience thrust force in the ratio of \(1:2\), then the ratio of the masses of the balls will be:
1. \(1:1\)
2. \(1:2\)
3. \(2:1\)
4. \(1:4\)
1. | \(P_P=P_Q=P_R=P_S\) | 2. | \(P_P>P_Q>P_R>P_S\) |
3. | \(P_P<P_Q<P_R<P_S\) | 4. | The data is insufficient to predict the relation |
The reading of a spring balance when a block is suspended from it in the air is 60 N. This reading is changed to 40 N when the block is submerged in water. The specific gravity of the block, therefore, must be:
1. 3
2. 2
3. 6
4. 3/2
A beaker full of water is placed on a spring balance. If we put our finger in water without touching the beaker, how will the reading of the balance change?
[Take \(ρ _{finger} > ρ _{wate r}\)]
1. | Increase | 2. | Decrease |
3. | Remain the same | 4. | Will be halved |
If a capillary tube is partially dipped vertically into liquid and the levels of the liquid inside and outside are the same, then the angle of contact is:
1. | \(90^\circ\) | 2. | \(30^\circ\) |
3. | \(45^\circ\) | 4. | \(0^\circ\) |
From the given diagram, what is the velocity \(v_3?\)
1. \(4~\text{m/s}\)
2. \(3~\text{m/s}\)
3. \(1~\text{m/s}\)
4. \(2~\text{m/s}\)