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Q. No.Young's double-slit experiment is conducted with light of wavelength \(\lambda.\) The double-slit is shifted towards the source by a distance \(L,\) and the position of the \(5^{\text{th}}\) fringe is shifted by:
1.
\(\dfrac{5\lambda D}{d}\)
2.
\(\dfrac{5\lambda L}{d}\)
3.
\(\dfrac{5\lambda (L+D)}{d}\)
4.
\(\dfrac{5\lambda (L-D)}{d}\)
Subtopic: Â Young's Double Slit Experiment |
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In a Young's double-slit experiment with identical slits (of slit separation-\(d,\) slit to screen distance \(D\)), the phase difference between the waves arriving at a point just opposite to one of the slits is \(\dfrac{\pi}{2}.\) The source is placed symmetrically with respect to the slits. The wavelength of light is:
| 1. | \(\dfrac{2d^2}{D}\) | 2. | \(\dfrac{d^2}{2D}\) |
| 3. | \(\dfrac{d^2}{D}\) | 4. | \(\dfrac{D^2}{d}\) |
Subtopic: Â Young's Double Slit Experiment |
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Sound waves travel faster in water than in air. Imagine a plane sound wavefront incident at an angle \(\alpha\) at the air-water interface; the refracted wavefront making an angle \(\beta\) with the interface. Then,
| 1. | \(\alpha>\beta\) |
| 2. | \(\beta>\alpha\) |
| 3. | \(\alpha=\beta\) |
| 4. | the relation between \(\alpha~\&~\beta \) cannot be predicted. |
Subtopic: Â Huygens' Principle |
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Young's double-slit experiment is conducted with light of an unknown wavelength, the waves arriving at the central point on the screen are found to have a phase difference of \(\dfrac{\pi}{2}.\) The closest maximum to the central point is formed behind one of the slits. The separation between the slits is \(d,\) and the slit to screen separation is \(D.\) The longest wavelength for this to happen is:
| 1. | \(\dfrac{2d^2}{D}\) | 2. | \(\dfrac{2d^2}{3D}\) |
| 3. | \(\dfrac{d^2}{2D}\) | 4. | \(\dfrac{d^2}{6D}\) |
Subtopic: Â Young's Double Slit Experiment |
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Young's double-slit experiment is performed with identical slits separated by a distance \(d,\) and with light of wavelength \(\lambda.\) The screen is placed at a point which is at a distance \(D\) from the double-slit, as usual. A convex lens of focal length \(f\) is inserted between the double-slit and the screen, very close to the double slit. The screen is adjusted (i.e. the value of \(D\) is slowly varied) until a clear interference pattern is formed. The fringe width equals:
| 1. | \(\dfrac{\lambda f}{d}\) | 2. | \(\dfrac{2\lambda f}{d}\) |
| 3. | \(\dfrac{\lambda f}{2d}\) | 4. | \(\dfrac{\lambda f}{d\sqrt2}\) |
Subtopic: Â Young's Double Slit Experiment |
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A monochromatic light of frequency \(500~\text{THz}\) is incident on the slits of Young's double slit experiment. If the distance between the slits is \(0.2~\text{mm}\) and the screen is placed at a distance \(1~\text{m}\) from the slits, the width of \(10\) fringes will be:
| 1. | \(1.5~\text{mm}\) | 2. | \(15~\text{mm}\) |
| 3. | \(30~\text{mm}\) | 4. | \(3~\text{mm}\) |
Subtopic: Â Young's Double Slit Experiment |
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Which of the following colourful patterns is due to the diffraction of light?
1. Rainbow
2. White light dispersed using a prism
3. Colours observed on compact disc
4. Blue colour of the sky
1. Rainbow
2. White light dispersed using a prism
3. Colours observed on compact disc
4. Blue colour of the sky
Subtopic: Â Diffraction |
From NCERT
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Consider the diffraction of light through a rectangular slit which is twice as wide as it is high. Which of the following statements is true?
| 1. | The central diffraction peak is wider in the vertical direction than in the horizontal direction. |
| 2. | The central diffraction peak is wider in the horizontal direction than in the vertical direction. |
| 3. | The central diffraction peak is equally wide in both horizontal and vertical directions. |
| 4. | The width of the central diffraction peak is independent of the wavelength of light used. |
Subtopic: Â Diffraction |
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Consider a parallel beam of monochromatic light of wavelength \(600~\text{nm}.\) It is allowed to pass through a slit of width \(0.15~\text{mm}.\) Assume that the angles involved are very small. The angular divergence in which most of the light gets diffracted will be:
1. \(4\times 10^{-3}~\text{rad}\)
2. \(2.0\times10^{-3}~\text{rad}\)
3. \(8.0\times10^{-3}~\text{rad}\)
4. \(90^\circ\)
1. \(4\times 10^{-3}~\text{rad}\)
2. \(2.0\times10^{-3}~\text{rad}\)
3. \(8.0\times10^{-3}~\text{rad}\)
4. \(90^\circ\)
Subtopic: Â Diffraction |
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Light of wavelength \(\lambda\) falls perpendicularly onto a single slit of width \(d\). A diffraction maximum is formed at \(P\) on a faraway screen placed parallel to plane of the slit. The first diffraction minimum is formed at \(Q,\) as shown on the screen. Let \(C\) be a 'point' so that it divides the slit \(AB\) in the ratio \(\dfrac{AC}{CB}=\dfrac12,\) i.e. \(AC\) represents the upper \(\dfrac13^{rd}\) of the slit. The total amplitude of the oscillation arriving from \(AC\) at \(Q\) is \(A_1\) and from \(CB\) at \(Q\) is \(A_2\).
Then:
1. \(2 A_{1}=A_{2}\)
2. \(A_{1}=2 A_{2}\)
3. \(\sqrt{2} A_{1}=A_{2}\)
4. \(A_{1}=A_{2}\)
Then:
1. \(2 A_{1}=A_{2}\)
2. \(A_{1}=2 A_{2}\)
3. \(\sqrt{2} A_{1}=A_{2}\)
4. \(A_{1}=A_{2}\)
Subtopic: Â Diffraction |
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