- 1(current)
Q. No.A force \(F = (20 + 10 y)\) acts on a particle in the \(y\)-direction where \(F\) is in Newton and \(y\) is in meter. Work done by this force to move the particle from \(y =0\) to \(y =1\) m is:
1. \(20~\text{J}\)
2. \(30~\text{J}\)
3. \(5~\text{J}\)
4. \(25~\text{J}\)
1. \(20~\text{J}\)
2. \(30~\text{J}\)
3. \(5~\text{J}\)
4. \(25~\text{J}\)
Subtopic: Â Work Done by Variable Force |
 74%
From NCERT
NEET - 2019
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh
An object of mass \(500\) g initially at rest is acted upon by a variable force whose x-component varies with \(x\) in the manner shown. The velocities of the object at the points \(x=8\) m and \(x=12\) m would have the respective values of nearly:
| 1. | \(18\) m/s and \(22.4\) m/s | 2. | \(23\) m/s and \(22.4\) m/s |
| 3. | \(23\) m/s and \(20.6\) m/s | 4. | \(18\) m/s and \(20.6\) m/s |
Subtopic: Â Work Done by Variable Force |
 59%
From NCERT
NEET - 2019
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
Links
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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