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Q. No.A network of resistors is connected across a \(10~\text{V}\) battery with an internal resistance of \(1~\Omega\) as shown in the circuit diagram. The equivalent resistance of the circuit is:
1. \(\dfrac{17}{3}~\Omega\)
2. \(\dfrac{14}{3}~\Omega\)
3. \(\dfrac{12}{7}~\Omega\)
4. \(\dfrac{14}{7}~\Omega\)
1. \(\dfrac{17}{3}~\Omega\)
2. \(\dfrac{14}{3}~\Omega\)
3. \(\dfrac{12}{7}~\Omega\)
4. \(\dfrac{14}{7}~\Omega\)
Subtopic: Â Combination of Resistors |
 75%
Level 2: 60%+
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A cell of emf \(4~\text{V}\) and internal resistance \(0.5~\Omega\) is connected to a \(7.5~\Omega\) external resistance. The terminal potential difference of the cell is:
| 1. | \(3.75~\text{V}\) | 2. | \(4.25~\text{V}\) |
| 3. | \(4~\text{V}\) | 4. | \(0.375~\text{V}\) |
Subtopic: Â EMF & Terminal Voltage |
 75%
Level 2: 60%+
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The equivalent resistance of the infinite network given below is:
1. \(2~\Omega\)
2. \((1+\sqrt2)~\Omega\)
3. \((1+\sqrt3)~\Omega\)
4. \((1+\sqrt5)~\Omega\)
1. \(2~\Omega\)
2. \((1+\sqrt2)~\Omega\)
3. \((1+\sqrt3)~\Omega\)
4. \((1+\sqrt5)~\Omega\)
Subtopic: Â Combination of Resistors |
 55%
Level 3: 35%-60%
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Subtopic: Â Derivation of Ohm's Law |
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Level 1: 80%+
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The plot of current \(I~\text{(A)}\) flowing through a metallic conductor versus the applied voltage \(V~\text{(volt)}\) across the ends of a conductor is:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Â Derivation of Ohm's Law |
 80%
Level 1: 80%+
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A Wheatstone bridge is used to determine the value of unknown resistance \(X\) by adjusting the variable resistance \(Y\) as shown in the figure. For the most precise measurement of \(X\), the resistances \(P\) and \(Q\):
| 1. | do not play any significant role. |
| 2. | should be approximately equal to \(2X\). |
| 3. | should be approximately equal and are small. |
| 4. | should be very large and unequal. |
Subtopic: Â Wheatstone Bridge |
 75%
Level 2: 60%+
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A copper wire of length \(10\) m and radius \(\left({10^{-2}/\sqrt{\pi}}\right)\) m has an electrical resistance of \(10~\Omega.\) The current density in the wire for an electric field strength of \(10\) (V/m) is:
1. \(10^{5}\) A/m2
2. \(10^{4}\) A/m2
3. \(10^{6}\) A/m2
4. \(10^{-5}\) A/m2
1. \(10^{5}\) A/m2
2. \(10^{4}\) A/m2
3. \(10^{6}\) A/m2
4. \(10^{-5}\) A/m2
Subtopic: Â Current & Current Density |
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Level 2: 60%+
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Two resistors of resistance, \(100~\Omega\) and \(200~\Omega\) are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in \(100~\Omega\) resistor to that in \(200~\Omega\) resistor in a given time is:
1. \(4:1\)
2. \(1:2\)
3. \(2:1\)
4. \(1:4\)
1. \(4:1\)
2. \(1:2\)
3. \(2:1\)
4. \(1:4\)
Subtopic: Â Heating Effects of Current |
 71%
Level 2: 60%+
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In the Wheatstone Bridge arrangement shown, the resistance \(P\) is \(2~ \Omega.\) The bridge is initially balanced. If P and Q are interchanged: an amount equal to \(S\) has to be added to \(R\) to restore the balance. The resistance \(Q\) equals (nearly):
1. \(2 ~\Omega\)
2. \(3.2 ~\Omega\)
3. \(4 ~\Omega\)
4. \(6.4 ~\Omega\)
1. \(2 ~\Omega\)
2. \(3.2 ~\Omega\)
3. \(4 ~\Omega\)
4. \(6.4 ~\Omega\)
Subtopic: Â Wheatstone Bridge |
Level 3: 35%-60%
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The current flowing through the left \(20~\Omega\) resistor is:
| 1. | \(1~\text A\) | 2. | \(0.5~\text A\) |
| 3. | \(2.5~\text A\) | 4. | \(3~\text A\) |
Subtopic: Â Kirchoff's Voltage Law |
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Level 3: 35%-60%
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