Three resistors having resistances \(r_1, r_2~\text{and}~r_3\) are connected as shown in the given circuit. The ratio \(\frac{i_3}{i_1}\) of currents in terms of resistances used in the circuit is:
1. \(\frac{r_1}{r_1+r_2}\)
2. \(\frac{r_2}{r_1+r_3}\)
3. \(\frac{r_1}{r_2+r_3}\)
4. \(\frac{r_2}{r_2+r_3}\)
The effective resistance of a parallel connection that consists of four wires of equal length, equal area of cross-section, and same material is \(0.25~\Omega\). What will be the effective resistance if they are connected in series?
1. \(1~\Omega\)
2. \(4~\Omega\)
3. \(0.25~\Omega\)
4. \(0.5~\Omega\)
In a potentiometer circuit, a cell of emf \(1.5~\text{V}\) gives a balance point at 36 cm length of wire. If another cell of emf 2.5 V replaces the first cell, then at what length of the wire, the balance point occur?
1. 64 cm
2. 62 cm
3. 60 cm
4. 21.6 cm
Match Column I and Column II with appropriate relations.
| Column I | Column II | ||
| (A) | Drift Velocity | (P) | \(\dfrac{ \mathrm{m}}{\mathrm{ne}^2 \rho}\) |
| (B) | Electrical Resistivity | (Q) | \(nev_d\) |
| (C) | Relaxation Period | (R) | \(\dfrac{ \mathrm{eE}}{\mathrm{m}} \tau\) |
| (D) | Current Density | (S) | \(\dfrac{E}{J}\) |
| (A) | (B) | (C) | (D) | |
| 1. | (R) | (P) | (S) | (Q) |
| 2. | (R) | (Q) | (S) | (P) |
| 3. | (R) | (S) | (P) | (Q) |
| 4. | (R) | (S) | (Q) | (P) |
The equivalent resistance between \(A\) and \(B\) for the mesh shown in the figure is:
| 1. | \(7.2~\Omega\) | 2. | \(16~\Omega\) |
| 3. | \(30~\Omega\) | 4. | \(4.8~\Omega\) |
For the circuit given below, Kirchhoff's loop rule for the loop \(BCDEB\) is given by the equation:
| 1. | \(-{i}_2 {R}_2+{E}_2-{E}_3+{i}_3{R}_1=0\) |
| 2. | \({i}_2{R}_2+{E}_2-{E}_3-{i}_3 {R}_1=0\) |
| 3. | \({i}_2 {R}_2+{E}_2+{E}_3+{i}_3 {R}_1=0\) |
| 4. | \(-{i}_2 {R}_2+{E}_2+{E}_3+{i}_3{R}_1=0\) |
Two solid conductors are made up of the same material and have the same length and the same resistance. One of them has a circular cross-section of area \( 𝐴 _1\) and the other one has a square cross-section of area \(A_2.\) The ratio of \(𝐴 _1 / 𝐴 _2 \) is:
| 1. | \(1.5\) | 2. | \(1\) |
| 3. | \(0.8\) | 4. | \(2\) |
For the circuit shown in the figure, the current \(I\) will be:

| 1. | \(0.75~\text{A}\) | 2. | \(1~\text{A}\) |
| 3. | \(1.5~\text{A}\) | 4. | \(0.5~\text{A}\) |