Q. No. The equation \(y=A \text{cos}(kx-\omega t )\) represents a wave motion with:
1.
amplitude \(A\), frequency \(\dfrac{\omega}{2\pi}\)
2.
amplitude \(\dfrac{A}{2}\), frequency \(\dfrac{2\omega}{\pi}\)
3.
amplitude \(2A,\) frequency \(\dfrac{\omega}{4\pi}\)
4.
does not represent a wave motion
The temperature at which the velocity of sound in air becomes double its velocity at \(0^\circ \text{C}\) is:
| 1. | \(435^\circ \text{C}\) | 2. | \(694^\circ \text{C}\) |
| 3. | \(781^\circ \text{C}\) | 4. | \(819^\circ \text{C}\) |
The speed of sound in air at NTP is \(720 ~\text{m/s}.\) If the pressure is increased to \(9\) times the atmospheric pressure, then the speed of sound at the same temperature will be:
1. \(720 ~\text{m/s}\)
2. \(960 ~\text{m/s}\)
3. \(320\sqrt{3} ~\text{m/s}\)
4. \(320 ~\text{m/s}\)
If the speed of sound in air is \(v,\) then the minimum possible length of the closed-end organ pipe which resonates to frequency \(f\) will be:
| 1. | \(\dfrac{v}{2f}\) | 2. | \(\dfrac{v}{4f}\) |
| 3. | \(\dfrac{v}{3f}\) | 4. | \(\dfrac{v}{f}\) |
| 1. | \(\dfrac{6}{5}\) | 2. | \(\dfrac{20}{3}\) |
| 3. | \(\dfrac{14}{5}\) | 4. | \(\dfrac{9}{7}\) |
| 1. | a wave traveling in the positive x-direction with a velocity \(1.5~\text{m/s} \) |
| 2. | a wave traveling in the negative x-direction with a velocity \(2.5~\text{m/s} \) |
| 3. | a wave traveling in the negative x-direction having a wavelength \(0.2~\text{m} \) |
| 4. | a wave traveling in the positive x-direction having a wavelength \(0.2~\text{m} \) |
\(y = 7\sin\left(7\pi t-0.04x+ \dfrac{\pi}{3}\right)\)
where, \(x\) is in metres and \(t\) in seconds. The speed of the wave is:
1. \(175\pi~\text{m/s}\)
2. \(49\pi~\text{m/s}\)
3. \(\dfrac{49}{\pi}~\text{m/s}\)
4. \(0.28\pi~\text{m/s}\)
| 1. | \(49~\text{N}\) | 2. | \(64~\text{N}\) |
| 3. | \(25~\text{N}\) | 4. | none of these |
1. \(\frac{{n}_{2}}{n}{+}{n}_{2}\)
2. \(n_2n\)
3. \({n}_{2}\pm{n}\)
4. \(\frac{{n}_{2}}{n}{-}{n}_{2}\)
The frequency of vibration of a tuning fork is \(400~\text{Hz}.\) If the velocity of sound in air is \(330~\text{m/s},\) then how far the sound has traversed while the tuning fork completes \(40\) vibrations?
1. \(24~\text m \)
2. \(57~\text m \)
3. \(42~\text m \)
4. \(33~\text m \)
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