The pendulum \(OA\) has a length \(L.\) The bob \(A\) is given an initial velocity towards right when it is at its lowest position. Thereafter it moves in a circular path and collides with the hard surface (at \(60^{\circ}\)) losing \(50\%\) of the kinetic energy it had just before the collision. The pendulum rebounds and it reaches a height of \(\dfrac{3L}{4}\) above its lowest point \(A\). In the absence of the hard surface, it would have risen to a height of:
           
1. \(\dfrac{3L}{2}\) 2. \(\dfrac{5L}{2}\)
3. \(2L\) 4. \(L\)
Subtopic:  Gravitational Potential Energy |
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NEET 2026 - Target Batch - Vital
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