The pendulum \(OA\) has a length \(L.\) The bob \(A\) is given an initial velocity towards right when it is at its lowest position. Thereafter it moves in a circular path and collides with the hard surface (at \(60^{\circ}\)) losing \(50\%\) of the kinetic energy it had just before the collision. The pendulum rebounds and it reaches a height of \(\dfrac{3L}{4}\) above its lowest point \(A\). In the absence of the hard surface, it would have risen to a height of:
1.
\(\dfrac{3L}{2}\)
2.
\(\dfrac{5L}{2}\)
3.
\(2L\)
4.
\(L\)
Add Note
Subtopic: Â Gravitational Potential Energy |
From NCERT
Other Reason
Highlight in NCERT
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.