In vernier callipers, \(20\) VSD coincides with \(16\) MSD (each division of length \(1\) mm). The least count of the vernier callipers is:
1. \(0.01\) cm
2. \(0.1\) cm
3. \(0.02\) cm
4. \(0.2\) cm
Subtopic:  Measurement & Measuring Devices |
 59%
Level 3: 35%-60%
NEET - 2026
Please attempt this question first.
Hints
Please attempt this question first.

One main scale division of a Vernier calliper is equal to \(1\) mm and the number of divisions on the Vernier scale is \(10.\) When both the jaws touch each other, the Vernier scale shifts to the left of zero of the main scale in such a way that \(4^\mathrm{th}\) Vernier division coincides with a division of the main scale. If this Vernier calliper measures the length of a wire to be \(1\) cm, the actual length of the wire is:
1. \(1.06\) cm 2. \(0.60\) cm
3. \(0.96\) cm 4. \(1.00\) cm
Subtopic:  Measurement & Measuring Devices |
Level 3: 35%-60%
NEET - 2026
Please attempt this question first.
Hints
Please attempt this question first.

Which of the following measurements require 'index correction'?
1. Measurement of speed of sound using resonance tube
2. Measurement of resistance of a wire using a metre bridge
3. Measurement of gravitational acceleration using simple pendulum
4. Measurement of focal length of lenses using optical bench
Subtopic:  Measurement & Measuring Devices |
Level 3: 35%-60%
NEET - 2026
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its \(10\) Vernier Scale Divisions (V.S.D.) are equal to its \(9\) Main Scale Divisions (M.S.D.). The least division in the M.S. is \(0.1\text{ cm}\) and the zero of V.S. is at \(x=0.1~ \text{cm}\) when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is \({M}=5~\text{cm}\) and the number of coinciding vernier division is \(8 ,\) the measured diameter after zero error correction, is:
1. \(4.98 ~\text{cm}\) 2. \(5.00 ~\text{cm}\)
3. \(5.18 ~\text{cm}\) 4. \(5.08 ~\text{cm}\)
Subtopic:  Measurement & Measuring Devices |
Level 3: 35%-60%
NEET - 2025
Please attempt this question first.
Hints
Please attempt this question first.

In a vernier callipers, \((N+1)\) divisions of the vernier scale coincide with \(N\) divisions of the main scale. If \(1\) \(\text{MSD}\) represents \(0.1~\text{mm}\), the vernier constant (in \(\text{cm}\)) is:
1. \(\dfrac{1}{100(N+1)} \) 2. \(100N\)
3. \(10(N+1) \) 4. \(\dfrac{1}{10 N}\)
Subtopic:  Measurement & Measuring Devices |
 71%
Level 2: 60%+
NEET - 2024
Hints

A vernier calipers has \(1~\text{mm}\) marks on the main scale. It has \(20\) equal divisions on the vernier scale which match with \(16\) main scale divisions. The least count of this vernier calipers is:
1. \(0.02~\text{mm}\) 2. \(0.05~\text{mm}\)
3. \(0.10~\text{mm}\) 4. \(0.20~\text{mm}\)
Subtopic:  Measurement & Measuring Devices |
 69%
Level 2: 60%+
NEET - 2024
Hints

advertisementadvertisement

The pitch of an error-free screw gauge is \(1~\text{mm},\) and there are \(100\) divisions on the circular scale. While measuring the diameter of a thick wire, the pitch scale reads \(1~\text{mm},\) and \(63^\text{rd}\) division on the circular scale coincides with the reference line. The diameter of the wire is:
1. \(1.63 ~\text{cm}\) 2. \(0.163 ~\text{cm}\)
3. \(0.163~\text m\) 4. \(1.63 ~\text m\)
Subtopic:  Measurement & Measuring Devices |
 71%
Level 2: 60%+
NEET - 2024
Hints

The diameter of a spherical bob, when measured with vernier callipers yielded the values: \(3.33\) cm, \(3.32\) cm, \(3.34\) cm, \(3.33\) cm and \(3.32\) cm. The mean diameter to appropriate significant figures is:
1. \(3.328\) cm
2. \(3.3\) cm
3. \(3.33\) cm
4. \(3.32\) cm
Subtopic:  Measurement & Measuring Devices |
 59%
Level 3: 35%-60%
NEET - 2023
Hints

When the circular scale of a screw gauge completes \(2\) rotations, it covers \(1\) mm over the pitch scale. The total number of circular scale divisions is \(50.\) The least count of the screw gauge in metres is:
1. \(10^{-4}\)
2. \(10^{-5}\)
3. \(10^{-2}\)
4. \(10^{-3}\)

Subtopic:  Measurement & Measuring Devices |
 57%
Level 3: 35%-60%
NEET - 2022
Hints

advertisementadvertisement

A screw gauge gives the following readings when used to measure the diameter of a wire:
Main scale reading: \(0\) mm
Circular scale reading: \(52\) divisions 
Given that \(1\) mm on the main scale corresponds to \(100\) divisions on the circular scale, the diameter of the wire that can be inferred from the given data is:

1. \(0.26\) cm 2. \(0.052\) cm
3. \(0.52\) cm 4. \(0.026\) cm
Subtopic:  Measurement & Measuring Devices |
 70%
Level 2: 60%+
NEET - 2021
Hints
Links