| A. | Cut the DNA with blunt end |
| B. | Cut the DNA with sticky end |
| C. | Recognises a specific palindromic sequence. |
| D. | Cut the DNA between the base G and A where it encounters the DNA sequence 'GAATTC' |
| E. | Exonuclease |
| 1. | B,C,E only | 2. | A,D,E only |
| 3. | A,C,D only | 4. | B,C,D only |
| 1. | Separated DNA fragments can be directly seen under UV radiation |
| 2. | Separated DNA can be extracted from gel piece. |
| 3. | Fragments of DNA move toward anode. |
| 4. | Sieving effect of agarose gel helps in separation of DNA fragments. |
| 1. | recognition sequence | 2. | cloning site |
| 3. | restriction site | 4. | ori site |
| Statement I: | Restriction Endonuclease finds its specific recognition sequence and binds to the DNA. |
| Statement II: | Restriction Endonuclease cuts each of the two strands of the double helix at specific points in their sugar phosphate backbones. |
| List-I | List-II | ||
| A. | Ampicillin | I. | Restriction sites |
| B. | Ori | II. | Blue/White screening |
| C. | Multiple cloning sites | III. | Selectable marker |
| D. | \(\beta\) galactosidase gene | IV. | Sequence from where replication starts |
| 1. | The gene 'X' is responsible for controlling the copy number of the linked DNA and 'Y' for protein involved in the replication of Plasmid. |
| 2. | The gene 'X' is 'for protein involved in replication of Plasmid and 'Y' for resistance to antibiotics. |
| 3. | Gene 'X' is responsible for recognition sites and 'Y' is responsible for antibiotic resistance. |
| 4. | The gene 'X' is responsible for resistance to antibiotics and 'Y' for protein involved in the replication of Plasmid. |