1.00 g of non-electrolyte solute (molar mass 250 g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 mol-1 kg K, the freezing point of benzene will be lowered by:

1. 0.4 K

2. 0.3 K

3. 0.5 K

4. 0.2 K

Subtopic:  Elevation of Boiling Point |
 84%
From NCERT
AIPMT - 2006
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A solution that has the highest boiling point among the following is:

1. 1.0 M NaOH

2. 1.0 M Na2SO4 

3. 1.0 M NH4NO3

4. 1.0 M KNO3

Subtopic:  Elevation of Boiling Point |
 83%
From NCERT
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The unit of Ebullioscopic constant is:

1. K kg mol–1 or K (molality)–1

2. mol kg K–1 or K–1 (molality)

3. kg mol–1 K–1 or K–1 (molality)–1

4. K mol kg–1 or K (molality)

Subtopic:  Elevation of Boiling Point |
 80%
From NCERT
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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
 59%
From NCERT
NEET - 2016
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Aluminium phosphate is 100 % ionized in 0.01 m aqueous solution. Hence, Tb/kb is-

1. 0.01 m 2. 0.015 m
3. 0.0175 m 4. 0.02 m
Subtopic:  Elevation of Boiling Point |
 62%
From NCERT
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Match the laws/colligative properties given in Column-I with expressions given in Column-II.

Column-I Column-II
A. Raoult’s law I. \(\mathrm{\pi=C R T}\)
B. Osmotic pressure  II. \(\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{K}_{\mathrm{f}} \mathrm{~m}\)
C. Elevation of boiling point III. \(\mathrm{p=x_1 p_1^0+x_2 p_2^0}\)
D. Depression in freezing point IV. \(\Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \mathrm{~m}\)

Codes:

A B C D
1. I III IV I
2. I II III IV
3. I IV III II
4. III I IV II
Subtopic:  Elevation of Boiling Point | Depression of Freezing Point |
 94%
From NCERT
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