The correct hybridization states of carbon atoms in the following compound are -
| 1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C 3 = sp3 |
| 3. | C1= sp2 , C2= sp2 , C 3 = sp | 4. | C1= sp3 , C2= sp3 , C 3 = sp3 |
The number of σ and π bonds in the molecule are -
| 1. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
| 2. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
| 3. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
| 4. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
The number of primary carbon atoms in the following compound are:

| 1. | 6 | 2. | 2 |
| 3. | 4 | 4. | 3 |
The \(C - H\) bond distance is longer in -
| 1. | \(C_2H_2\) | 2. | \(C_2H_4\) |
| 3. | \(C_2H_6\) | 4. | \(C_2H_2Br_2\) |

| 1. | Four (4) | 2. | Eight (8) |
| 3. | Twelve (12) | 4. | Sixteen (16) |