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Q. No.Which of the following statements about an electron is/are correct?
(a)
It has a negative charge and is lighter than a proton.
(b)
It has a negative charge and is heavier than a proton.
(c)
Its position is less fixed than that of a proton.
(d)
Its position is more fixed than that of a proton.
1.
(a) only
2.
(a) and (c)
3.
(b) and (d)
4.
(c) only
Subtopic: Introduction of Atomic Structure |
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Determine the minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal:
[Given: The threshold frequency of platinum is \(1.3\times10^{15}\text{s}^{-1}\) and \(\text{h}=6.6\times10^{-34}~\text{Js}.]\)
[Given: The threshold frequency of platinum is \(1.3\times10^{15}\text{s}^{-1}\) and \(\text{h}=6.6\times10^{-34}~\text{Js}.]\)
| 1. | \(3.21\times 10^{-14}~\text{J}\) | 2. | \(6.24\times 10^{-16}~\text{J}\) |
| 3. | \(8.58\times 10^{-19}~\text{J}\) | 4. | \(9.76\times 10^{-20}~\text{J}\) |
Subtopic: Photo Electric Effect |
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The de Broglie wavelength of an electron and a neutron become equal when the velocity of the electron is x times the velocity of the neutron. The value of x is:
[Given: Mass of electron is \(9.1 \times 10^{-31} \text {kg}\) and mass of neutron is \( 1.6 \times 10^{-27} \mathrm{~kg} \)]
| 1. | 1758 | 2. | 3054 |
| 3. | 1239 | 4. | 6215 |
Subtopic: Planck's Theory |
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Given below are the quantum numbers for 4 electrons.
A. n = 3, l = 2, ml = 1, ms = +1/2
B. n = 4, l = 1, ml = 0, ms = +1/2
C. n = 4, l = 2, ml = –2, ms = –1/2
D. n = 3, l = 1, ml = –1, ms = +1/2
The correct order of increasing energy is:
1. D < B < A < C
2. D < A < B < C
3. B < D < A < C
4. B < D < C < A
A. n = 3, l = 2, ml = 1, ms = +1/2
B. n = 4, l = 1, ml = 0, ms = +1/2
C. n = 4, l = 2, ml = –2, ms = –1/2
D. n = 3, l = 1, ml = –1, ms = +1/2
The correct order of increasing energy is:
1. D < B < A < C
2. D < A < B < C
3. B < D < A < C
4. B < D < C < A
Subtopic: Pauli's Exclusion Principle & Hund's Rule |
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Which of the following series of transition metal ions has the same 3d electronic configuration for all its metal ions?
1. \(\mathrm{Ti}^{2+}, \mathrm{V}^{3+}, \mathrm{Cr}^{4+}, \mathrm{Mn}^{5+}\)
2. \(\mathrm{Ti}^{3+}, \mathrm{V}^{2+}, \mathrm{Cr}^{3+}, \mathrm{Mn}^{4+}\)
3. \(\mathrm{Ti}^{+}, \mathrm{V}^{4+}, \mathrm{Cr}^{6+}, \mathrm{Mn}^{7+}\)
4. \(\mathrm{Ti}^{4+}, \mathrm{V}^{3+}, \mathrm{Cr}^{2+}, \mathrm{Mn}^{3+}\)
1. \(\mathrm{Ti}^{2+}, \mathrm{V}^{3+}, \mathrm{Cr}^{4+}, \mathrm{Mn}^{5+}\)
2. \(\mathrm{Ti}^{3+}, \mathrm{V}^{2+}, \mathrm{Cr}^{3+}, \mathrm{Mn}^{4+}\)
3. \(\mathrm{Ti}^{+}, \mathrm{V}^{4+}, \mathrm{Cr}^{6+}, \mathrm{Mn}^{7+}\)
4. \(\mathrm{Ti}^{4+}, \mathrm{V}^{3+}, \mathrm{Cr}^{2+}, \mathrm{Mn}^{3+}\)
Subtopic: Pauli's Exclusion Principle & Hund's Rule |
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The quantum number of 20th electron of Fe (Z=26) would be:
1. 3, 2, -2, -1/2
2. 3, 2, 0, 1/2
3. 4, 0, 0, -1/2
4. 4, 1, -1, +1/2
1. 3, 2, -2, -1/2
2. 3, 2, 0, 1/2
3. 4, 0, 0, -1/2
4. 4, 1, -1, +1/2
Subtopic: Quantum Numbers & Schrodinger Wave Equation |
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According to Bohr's model, the radius of the third orbit of the hydrogen atom is:
1. Three times the radius of the first orbit2. Five times the radius of the first orbit
3. Equal to the radius of the first orbit
4. Nine times the radius of the first orbit
Subtopic: Bohr's Theory |
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What is the maximum number of electrons that can fill a specific energy level?
1. \(2n\)
2. \(n\)
3. \(2n^2 + 1 \)
4. \(2n^2\)
1. \(2n\)
2. \(n\)
3. \(2n^2 + 1 \)
4. \(2n^2\)
Subtopic: Shell & Subshell |
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A source of monochromatic radiation of wavelength \(400~ nm\) provides \(1000 ~J\) of energy in \(10\) seconds. When this radiation falls on the surface of sodium, \(x\times 10^{20}\) electrons are ejected per second. Assume that wavelength \(400 ~nm\) is sufficient for ejection of electron from the surface of sodium metal. The value of \(x\) is: (Nearest integer)
[Given: \(h = 6.626 \times 10^{–34}~ Js\)]
1. Four (4)
2. Two (2)
3. Six (6)
4. Eight (8)
[Given: \(h = 6.626 \times 10^{–34}~ Js\)]
1. Four (4)
2. Two (2)
3. Six (6)
4. Eight (8)
Subtopic: Photo Electric Effect |
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The energy required to break a chemical bond is 3.313 × 10⁻¹² erg. Calculate the wavelength of the radiation (in cm) that can break this bond.
[Given: Speed of light, c = 3.00 × 10¹⁰ cm s⁻¹; Planck’s constant, h = 6.626 × 10⁻²⁷ erg s]
2. \(1.00 \times 10^{-5}\mathrm {cm}\)
3. \(2.00 \times 10^{-5} \mathrm {cm}\)
4. \(6.00 \times 10^{-5}\mathrm {cm}\)
Subtopic: Planck's Theory |
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