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Q. No.Which set of quantum numbers is not possible?
1. n = 2, l = 1, ml = +1, ms = –1⁄2
2. n = 3, l = 2, ml = +1, ms= +1⁄2
3. n = 4, l = 4, ml = –1, ms = +1⁄2
4. n =5, l = 2, ml = +2, ms = –1⁄2
Subtopic: Quantum Numbers & Schrodinger Wave Equation |
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Identify pair of symbols that represents nuclei that have the same number of neutrons.
1. \({ }_{26}^{56} \mathrm{Fe}\text{ and }{ }_{28}^{58} \mathrm{Ni} \)
2. \({ }_{26}^{58} \mathrm{Fe}\text{ and }{ }_{26}^{56} \mathrm{Fe}^{2+} \)
3. \({ }_{27}^{57} \mathrm{Co}\text{ and }{ }_{28}^{57} \mathrm{Ni} \)
4. \({ }_{28}^{57} \mathrm{Ni}\text{ and }{ }_{28}^{58} \mathrm{Ni} \)
1. \({ }_{26}^{56} \mathrm{Fe}\text{ and }{ }_{28}^{58} \mathrm{Ni} \)
2. \({ }_{26}^{58} \mathrm{Fe}\text{ and }{ }_{26}^{56} \mathrm{Fe}^{2+} \)
3. \({ }_{27}^{57} \mathrm{Co}\text{ and }{ }_{28}^{57} \mathrm{Ni} \)
4. \({ }_{28}^{57} \mathrm{Ni}\text{ and }{ }_{28}^{58} \mathrm{Ni} \)
Subtopic: Number of Electron, Proton & Neutron |
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All of the energy levels listed below are allowed, except one. Find that odd one out:
1. 3f
2. 4d
3. 5p
4. 7s
1. 3f
2. 4d
3. 5p
4. 7s
Subtopic: Shell & Subshell |
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A yellow lamp of power 100 W (J s–1) emits radiation of wavelength 560 nm. Calculate the total number of photons emitted by the lamp in 1.0 s:
| 1. | 1.6 × 1018 | 2. | 1.4 × 1018 |
| 3. | 2.8 × 1020 | 4. | 2.1 × 1020 |
Subtopic: Electromagnetic Radiation |
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The Heisenberg Uncertainty Principle states that it is impossible to simultaneously know both the exact position (x) and exact momentum (p) of a particle with arbitrary precision.
Mathematically, it is expressed as
1. \(\Delta x \geq \frac{\Delta p \times h}{4 \pi} \)2. \(\Delta x \times \Delta p \geq \frac{h}{4 \pi} \)
3. \(\Delta x \times \Delta p < \frac{h}{4\pi} \)
4. \(\Delta p \geq \frac{\pi h}{\Delta x} \)
Subtopic: Heisenberg Uncertainty Principle |
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Calculate the de-Broglie wavelength for a particle having a mass of 1 kg and moving at a velocity of 100 m/s:
1. \(6.6 \times 10^{-33} \mathrm{~m}\)
2. \(6.6 \times 10^{-36} \mathrm{~m}\)
3. \(3.3 \times 10^{+33} \mathrm{~m}\)
4. \(3.3 \times 10^{-36} \mathrm{~m}\)
1. \(6.6 \times 10^{-33} \mathrm{~m}\)
2. \(6.6 \times 10^{-36} \mathrm{~m}\)
3. \(3.3 \times 10^{+33} \mathrm{~m}\)
4. \(3.3 \times 10^{-36} \mathrm{~m}\)
Subtopic: De Broglie Equation |
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Subtopic: Shell & Subshell |
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The energy of an electron in the first Bohr orbit is −13.6 eV. Based on this information, it can be concluded that the energy of Be3+ in the first excited state will be:
1. − 30.6 eV
2. − 40.8 eV
3. − 54.4 eV
4. + 40.8 eV
1. − 30.6 eV
2. − 40.8 eV
3. − 54.4 eV
4. + 40.8 eV
Subtopic: Bohr's Theory |
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Millikan’s Oil drop Method was used to determine:
1. Neutron
2. Alpha particle
3. Positron
4. Charge on the electrons
1. Neutron
2. Alpha particle
3. Positron
4. Charge on the electrons
Subtopic: Introduction of Atomic Structure |
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Level 2: 60%+
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Match Column-I (parameters) with Column-II (expressions) and mark the appropriate choice:
1. (A)→(iii), (B)→(iv), (C)→(i), (D)→(ii)
2. (A)→(ii), (B)→(i), (C)→(iv), (D)→(iii)
3. (A)→(iv), (B)→(iii), (C)→(i), (D)→(ii)
4. (A)→(i), (B)→(ii), (C)→(iv), (D)→(iii)
| Column-I (Parameters) |
Column-II (Expressions) |
||
| (A) | Uncertainty of an object | (i) | \({5.29 \times n^2} \over Z\) |
| (B) | Bohr's radius of an orbit | (ii) | \(h \over 4 \pi m\) |
| (C) | The angular momentum of an electron | (iii) | \(h \over mv\) |
| (D) | de Broglie wavelength | (iv) | \(n . { h \over 2 \pi}\) |
1. (A)→(iii), (B)→(iv), (C)→(i), (D)→(ii)
2. (A)→(ii), (B)→(i), (C)→(iv), (D)→(iii)
3. (A)→(iv), (B)→(iii), (C)→(i), (D)→(ii)
4. (A)→(i), (B)→(ii), (C)→(iv), (D)→(iii)
Subtopic: Bohr's Theory | Heisenberg Uncertainty Principle | De Broglie Equation |
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