| Assertion (A): | For n=3, l maybe 0,1 and 2 and m maybe 0; \(\pm\)1 and \(\pm\)2 |
| Reason (R): | For each value of n, there are 0 to (n-1) possible values of l; and for each value of l, there are 0 to \(\pm\)l values of m. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is false. |
| 4. | (A) is False but (R) is True. |
| Statement I: | |
| Statement II: |
| (i). | n (principal quantum number) can have values 1, 2, 3, 4, ....... |
| (ii). | The number of orbitals for a given value of l is (2l+1). |
| (iii). | The value of spin quantum numbers is always \(\pm\frac12\). |
| (iv). | For l=5, the total number of orbitals is 9. |
The threshold frequency of a metal is \(1.4 \times 10^{15}sec^{-1}\). Calculate the minimum energy required to eject a photoelectron from this metal.
[Given: Planck’s constant, \(h = 6.6 \times 10^{-34} J sec\)]
| 1. | \(n=1,l=0,m_l=0,m_s=-\frac12 \) |
| 2. | \(n=1,l=1,m_l=0,m_s=+\frac12 \) |
| 3. | \(n=2,l=1,m_l=0,m_s=+\frac12 \) |
| 4. | \(n=3,l=1,m_l=0,m_s=+\frac12 \) |
| List-I (quantum number) |
List-II (Orbital) |
||
| (A) | n = 2, \(\ell\) = 1 | (I) | 2s |
| (B) | n = 3, \(\ell\) = 2 | (II) | 3s |
| (C) | n = 3, \(\ell\) = 0 | (III) | 2p |
| (D) | n = 2, \(\ell\) = 0 | (IV) | 3d |
| (A) | (B) | (C) | (D) | |
| 1. | (III) | (IV) | (I) | (II) |
| 2. | (IV) | (III) | (I) | (II) |
| 3. | (IV) | (III) | (II) | (I) |
| 4. | (III) | (IV) | (II) | (I) |