Match the quantum numbers in Column I with the corresponding orbitals in Column II:

	Column I		Column II
(A)	n = 2, l =1	(i)	4s
(B)	n = 4, l = 0	(ii)	2p
(C)	n = 5, l = 3	(iii)	3d
(D)	n = 3, l = 2	(iv)	5f

Select the correct option:

1. (A) - (iv); (B) - (ii); (C) - (i); (D) - (iii)

2. (A) - (ii); (B) - (iii); (C) - (iv); (D) - (i)

3. (A) - (ii); (B) - (i); (C) - (iv); (D) - (iii)

4. (A) - (iii); (B) - (ii); (C) - (i); (D) - (iv)

Which of the following is the correct order of filling of electrons, in the sixth period?

Determine the radius of the second Bohr orbit for hydrogen atom:

Given:
Planck's constant, h = 6.6262 × 10^–34 Js;
Mass of electron = 9.1091 × 10^–31 kg;
Charge of electron, e = 1.60210 ×10^–19 C;
Permittivity of vaccum, ∈₀ = 8.854185 ×10^–12 kg^–1m^–3A²

1. 0.529 Å

2. 2.12 Å

3. 1.65 Å

4. 7.76 Å

The total number of orbitals associated with the principal quantum number n = 3 are :

1. 3

2. 6

3. 9

4. 12

Find the de Broglie wavelength of a ball of mass 0.1 kg moving with a velocity of 10 m s⁻¹.

1. 662.6 × 10^–34 m

2. 66.26 × 10^–34 m

3. 6.626 × 10^–34 m

4. 6.626 × 10^–36 m

 In \(_{35}^{80}Br\), $$the number of protons, neutrons, and electrons are:${}_{\mathrm{}}{}^{\mathrm{}}$

1. 25, 45, 45

2. 35, 45, 35

3. 45, 45, 35

4. 80, 35, 35

The quantum number of four electrons are given below : 

The correct order of their increasing energies is:
1. I < III < II < IV
2. IV < II < III < I
3. I < II < III < IV
4. IV < III < II < I

According to Bohr's theory, what is the angular momentum of an electron located in the fifth orbit? 

1. $25\frac{h}{\mathrm{\pi }}$

2. $1.0\frac{h}{\mathrm{\pi }}$

3. $10\frac{h}{\mathrm{\pi }}$

4. $2.5\frac{h}{\mathrm{\pi }}$

The nuclei of which one of the following pairs are isotones:

Two sets of quantum numbers with the same number of radial nodes are :

1. n = 3, l = 0, m_l = 0  and n = 2, l = 0, m_l = 0

2. n = 3, l = 2, m_l = 0 and n = 2, l = 1, m_l = 0

3. n = 3, l = 1, m_l = –1 and n = 2, l = 1, m_l = 0

4. n = 3, l = 1, m_l = 1 and n = 2, l = 1, m_l = 0