Calculate the energy corresponding to light of wavelength 45 nm:
(Planck's constant h = 6.63 × 10^–34 Js & speed of light c = 3 × 10⁸ ms^–1)
1. 6.67 x 10¹⁵ J
2. 6.67 x 10¹¹ J
3. 4.42 x 10^-15 J
4. 4.42 x 10^-18 J

The value of Planck's constant is 6.63 × 10^–34 J s. The velocity of light is 3.0 × 10⁸ m s^–1. The closest value to the wavelength in nanometers of a quantum of light with a frequency of $8\times {10}^{15}$ ${\mathrm{s}}^{-1}$ is:

1. $2\times {10}^{-25}$

2. $5\times {10}^{-18}$

3. $4\times {10}^1$

4. $3\times {10}^7$

If the energy value is E = 3.03 × 10^–19 Joules, (h = 6.6×10^–34 J x sec., C = 3×10⁸ m/sec), then the value of the corresponding wavelength is: