A solution containing one mole per litre of each \(Cu(NO_3)_2; AgNO_3; Hg_2(NO_3)_2\) is being
electrolysed by using inert electrodes. The values of standard electrode potentials in volts
(reduction potentials) are: 
\(\begin{aligned} & \mathrm{Ag} / \mathrm{Ag}^{+}=+0.80,2 \mathrm{Hg} / \mathrm{Hg}_2^{++}=+0.79 \\ & \mathrm{Cu} / \mathrm{Cu}^{++}=+0.34, \mathrm{Mg} / \mathrm{Mg}^{++}=-2.37 \end{aligned}\)
With increasing voltage, the sequence of deposition of metals on the cathode will be :
1. Ag, Hg, Cu, Mg
2. Mg, Cu, Hg, Ag
3. Ag, Hg, Cu
4. Cu, Hg, Ag

Subtopic:  Electrode & Electrode Potential |
Level 4: Below 35%
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The standard reduction potentials of \(\mathrm{Cu}^{2+} \mid \mathrm{Cu} \text { and } \mathrm{Cu}^{2+} \mid \mathrm{Cu}^{+}\) are 0.337 V and 0.153V respectively. The standard electrode potential of Cu+|Cu half cell is: 

1. 0.184 V
2. 0.827 V
3. 0.521 V
4. 0.490 V
Subtopic:  Electrolytic & Electrochemical Cell |
Level 3: 35%-60%
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Identify the correct statement: 
1. The corrosion of iron can be minimised by forming contact with another metal with a higher reduction potential. 
2. Iron corrodes in oxygen-free water 
3. The corrosion of iron can be minimised by forming an impermeable barrier 
4. Iron corrodes more rapidly in salt water because its electrochemical potential is higher. 
Subtopic:  Corrosion |
Level 3: 35%-60%
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An aqueous solution of X is added slowly to an aqueous solution of Y as shown in List I. The variation in conductivity of these mixtures is given in List II. Match List I with List II and select the correct answer using the codes given below the table:
List-I List-II
(P) (i) Conductivity 
decreases and
then increases.
(Q) (ii) Conductivity 
decreases and
then does not
change much.
(R) (iii) Conductivity 
increases
and then does
not change
much.
(S) (iv) Conductivity
does not change
much and then 
increases.

Codes:
P Q R S
1. (iii) (iv) (ii) (i)
2. (iv) (iii) (ii) (i)
3. (ii) (iii) (iv) (i)
4. (i) (iv) (iii) (ii)
Subtopic:  Conductance & Conductivity |
Level 3: 35%-60%
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Half-Reaction \(E^o(V)\)
\(2H^+ + 2e^- \rightarrow H_2\) 0.00
\(Pd^{2+} + 2e^- \rightarrow Pd\) 0.90
\(O_2 + 4H^+ + 4e^- \rightarrow 2H_2O\) 1.23

According to the equations and data in the table above, which species is the strongest reducing agent of the following choices?

1. H+
2. H2
3. H2O
4. Pd2+
Subtopic:  Electrode & Electrode Potential |
 58%
Level 3: 35%-60%
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Extraction of chlorine from brine occurs when: 
 
1. \(\Delta G_V\) for the overall reaction is negative and EV for overall reaction has negative value.
2. \(\Delta G_V\) for the overall reaction is positive and EV for overall reaction has negative value.
3. \(\Delta G_V\) for the overall reaction is positive and EV for overall reaction has positive value.
4. \(\Delta G_V\) for the overall reaction is negative and EV for overall reaction has positive value.

Subtopic:  Relation between Emf, G, Kc & pH |
 72%
Level 2: 60%+
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For metal \('M',~E^o_3 \) for \(M^{+7}/M \) will be: 
1. 0.59 V
2. 2.07 V
3. 0.44 V
4. -0.59 V
Subtopic:  Electrode & Electrode Potential |
 57%
Level 3: 35%-60%
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The Incorrect statement about the conductivity of electrolytic (ionic) solutions is:
 
1.  It is independent of the solvent viscosity
2. It depends on the size of the ions and their solvation
3. It increases with the increase in electrolyte concentration
4. It increases with the increase in temperature 
Subtopic:  Conductance & Conductivity |
 62%
Level 2: 60%+
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Given below are two statements:
Assertion (A): Molar conductivity increases with a decrease in concentration.
Reason (R): For strong electrolytes, \(Λ_m\) increases slowly with dilution and can be represented by the equation:
\(\Lambda_m=\Lambda_m^0-A c^{1 / 2}\)
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Conductance & Conductivity |
 51%
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What is the nearest integer value of \(x\) for the Gibbs free energy change at 298 K, expressed as \(x×10^{−1}~kJ mol^{−1}\) for the given reaction.
\(Cu(s)+Sn^{2+}(0.001 M)\rightarrow Cu^{2+}(0.01M)+Sn(s) \)
Given: \(\small{E^\ominus_{Cu^{2+}/Cu}=0.34~V;~E^\ominus_{Sn^{2+}/Sn}=-0.14~V;~F=96500~C~mol^{-1}}\)
1. 873 
2. 983
3. 1002
4. 911

Subtopic:  Relation between Emf, G, Kc & pH |
 56%
Level 3: 35%-60%
JEE
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