(a)	Cl2(g)  ⇌ 2Cl(g) ; Kc = 5.0×10-39 mol/L
(b)	Cl2(g)   +   2NO(g)   ⇌   2NOCl(g)   ;   Kc =3.7×108 mol/L
(c)	Cl2(g) +   2NO2(g)   ⇌   2NO2Cl(g)   ;   Kc=1.8  mol/L

In which of the reactions given above, will there be an appreciable concentration of both reactant (s) and product (s)?
1. Only reaction (a)
2. Both reactions (a) and (b)  
3. Only reaction (c)
4. Only reaction (b) 

For the reaction, $3{\mathrm{O}}_2$ $\left(\mathrm{g}\right)$ $\rightleftharpoons$ $2{\mathrm{O}}_3$ $\left(\mathrm{g}\right),$ ${\mathrm{K}}_{\mathrm{c}}$ $=$ $2.0$ $\times$ ${10}^{-50}$ L/mol at 25^°C. If the equilibrium concentration of O₂ in air at 25^°C is $1.6$ $\times$ ${10}^{-2}$, the concentration of O₃ would be: 

$1.$ $2.86$ $\times {10}^{28}$ $\mathrm{M}$
$2.$ $28.66$ $\times$ ${10}^{-28}$ $\mathrm{M}$
$3.$ $1.43$ $\times$ ${10}^{-28}$ $\mathrm{M}$
$4.$ $2.86$ $\times$ ${10}^{-28}$ $\mathrm{M}$

Consider the following reaction:
\(CO_{\left(\right. g \left.\right)}\) \(+\) \(3 {H_{2}}_{\left(g\right)}\) \(\rightleftharpoons\) \({CH_{4}}_{\left(\right. g \left.\right)}\) \(\)\(+\) \(H_{2} O_{\left(\right. g \left.\right)}\) \(\)

If the reaction mixture contains 0.30 mol of CO, 0.10 mol of H_2, and 0.02 mol of H₂O, and an unknown amount of CH₄ at equilibrium at 1300 K in a 1L flask, the concentration of CH₄ in the mixture will be -

(K_c = 3.90 at 1300 K) $\mathrm{}$

1 . \(5 . 85\) \(\times\) \(10^2\) \(M\)
2 . \(5 . 85\) \(\times\) \(10^{- 1}\) \(M\)
3 . \(5 . 85\) \(\times\) \(10^3\) \(M\)
4 . \(5 . 85\) \(\times\) \(10^{- 2}\) \(M\)

The concentration of hydrogen ion in a sample of soft drink is $3.8$ $\times {10}^{-3}$ $\mathrm{M}$. The  pH of the soft drink will be:

What will be the concentration of H⁺ ions in a vinegar sample with a pH of 3.76?

$1.$ $8.95$
$2.$ $1.43$
$3.$ $3.56$
$4.$ $6.30$

(Atomic wt of Tl =204)

When 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution, the pH of the resultant solution will be:

A 0.001 M aniline solution has a pH of:
(\(K_b = 4.27 \times 10^{-10}\))

The degree of ionization of 0.05 M acetic acid is:

(pK_a = 4.74)