The compound \(PbI_4\) does not exist because:

1. \(Pb^{2+}\) is more stable than \(Pb^{4+}\).
2. \(I^-\) is better reducing agent.
3. \(Pb^{4+}\) is more stable than \(Pb^{2+}\).
4. \(I^-\) is better oxidising agent.
Subtopic:  Properties of Glass, Pb & Sn compounds |
Level 3: 35%-60%
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