From the following, the compound(s) that react(s) with \(\mathrm{BF}_3\) is/are -

1. Ethers 2. \( \mathrm{H}_2 \mathrm{O} \)
3. \(\mathrm{NH}_3 \) 4. All of the above

Subtopic:  Boron Family- Preparations, Properties & Uses |
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Na2B4O710H2O740C2NaBO2+(X)+10H2O
(X)+CaF2+H2SO4Y+CaSO4+H2O
(Y)+NaBH4(Z)+NaBF4

Select the incorrect statement regarding compounds (X), (Y) and (Z).

1.  Compound (X) is B2O3 and compound (Z) contains two 3C - 2e bonds

2.  Compound (X) is B2O3 and compound (Y) contains one 3C - 2e bonds 

3.  Compound (Y) is Lewis acid and stable due to pπ-pπ back bonding

4.  Compound (Z) reacts with excess of NH3 at high temperature gives inorganic graphite 

Subtopic:  Compounds of Boron- Preparations, Properties & Uses |
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Hydrolysis of BCl3 gives X which on treatment with sodium carbonate produces Y. X and Y, respectively, are 

1.  H3BO3andNaBO2

2.  H3BO3andNa2B4O7

3.  B2O3andNaBO2

4.  B2O3andNa2B4O7

Subtopic:  Compounds of Boron- Preparations, Properties & Uses |
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Ionization enthalpy (iH1kJmol-1) for the elements of Group 13 follows the order.

1. B > Al > Ga > In > Tl 2. B < Al < Ga < In < Tl
3. B < Al > Ga < In > Tl 4. B > Al < Ga > In < Tl
Subtopic:  Boron Family- Preparations, Properties & Uses |
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A compound X, of boron, reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas -

1. \(\mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 \) 2. \(\mathrm{B}_2 \mathrm{O}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 \)
3. \(\mathrm{BF}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 \) 4. \(\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6, \mathrm{~B}_2 \mathrm{H}_6\)
Subtopic:  Compounds of Boron- Preparations, Properties & Uses |
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Which does not show inert pair effect

(1) Al

(2) Sn

(3) Pb

(4) Thallium

Subtopic:  Boron Family- Preparations, Properties & Uses |
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BCl3 does not exist as dimer but BH3 exist as dimer B2H6 because:

1.chlorine is more electronegative than hydrogen

2.there is - back bonding in BCl3 but BH3 does not contain such multiple bonding

3.large sized chlorine atoms do not fit in between the small boron atoms whereas small sized hydrogen atoms get fitted between boron atoms

4.none of the above

Subtopic:  Boron Family- Preparations, Properties & Uses |
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Carbon dioxide is a gas but silica is a solid because:

1. Carbon dioxide is composed of discrete covalent CO2 molecules whereas silica has a continuous tetrahedral structure.

2. CO2 molecules are lighter than SiO2 molecules.

3. CO2 is more acidic than SiO2.

4. The melting point of silica is very high.

Subtopic:  Compounds of Carbon, Preparations, Properties & Uses |
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Na2B4O710H2O740C2NaBO2+(X)+10H2O
(X)+CaF2+H2SO4Y+CaSO4+H2O
(Y)+NaBH4(Z)+NaBF4

Select the incorrect statement regarding compounds (X), (Y) and (Z).

1.  Compound (X) is B2O3 and compound (Z) contains two 3C - 2e bonds

2.  Compound (X) is B2O3 and compound (Y) contains one 3C - 2e bonds 

3.  Compound (Y) is Lewis acid and stable due to pπ-pπ back bonding

4.  Compound (Z) reacts with excess of NH3 at high temperature gives inorganic graphite 

Subtopic:  Compounds of Boron- Preparations, Properties & Uses |
Level 3: 35%-60%
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A strong oxidizing agent among the following is -

1.  Tl3+

2.  Ga3+

3.  ln3+

4.  Al3+

Subtopic:  Boron Family- Preparations, Properties & Uses |
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Level 2: 60%+
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