The hydrolyzed product of an ester, when reduced by \(\mathrm{LiAlH}_4\), gives:
1. Two alcohols
2. Two aldehyde
3. One acid and one alcohol
4. Two acids
Intermediates formed during the reaction of \(RCONH_2\) with \(Br_ 2\) and \(KOH\) are:
1. RNHCOBr and RNCO
2. RCONHBr and RNCO
3. RNH-Br and RCONHBr
4. RCON
In the following reaction, product 'P' is:

1. RCH2OH
2. RCOOH
3. RCHO
4. RCH3
In the set of the given reactions, identify the product C:
\(\mathrm{CH_3COOH+PCl_5\rightarrow A\xrightarrow[Anh.AlCl_3]{C_6H_6}B\xrightarrow[ether]{C_2H_5MgBr}C}\)
| 1. | CH3CH(OH)C2H5 |
| 2. | CH3COC6H5 |
| 3. | CH3CH(OH)C6H5 |
| 4. |
When m-chlorobenzaldehyde is treated with 50% KOH solution, the product(s) obtained is (are):
| 1. | |
| 2. | |
| 3. | |
| 4. |