The hydrolyzed product of an ester, when reduced by \(\mathrm{LiAlH}_4\), gives:

1. Two alcohols

2. Two aldehyde

3. One acid and one alcohol

4. Two acids

Subtopic:  Acid Derivatives - Preparation, Properties & Uses |
 54%
Level 3: 35%-60%
AIPMT - 2000
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Intermediates formed during the reaction of \(RCONH_2\) with \(Br_ 2\) and \(KOH\) are:

1. RNHCOBr and RNCO

​2. RCONHBr and RNCO

3. RNH-Br and RCONHBr

4. RCONBr2

Subtopic:  Acid Derivatives - Preparation, Properties & Uses |
 63%
Level 2: 60%+
AIPMT - 2001
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In the following reaction, product 'P' is:

1. RCH2OH

2. RCOOH

3. RCHO

4. RCH3

Subtopic:  Acid Derivatives - Preparation, Properties & Uses |
 91%
Level 1: 80%+
AIPMT - 2002
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In the set of the given reactions, identify the product C:
 
\(\mathrm{CH_3COOH+PCl_5\rightarrow A\xrightarrow[Anh.AlCl_3]{C_6H_6}B\xrightarrow[ether]{C_2H_5MgBr}C}\)

1. CH3CH(OH)C2H5
2. CH3COC6H5
3. CH3CH(OH)C6H5
4.
Subtopic:  Acid Derivatives - Preparation, Properties & Uses |
 84%
Level 1: 80%+
AIPMT - 2003
Hints

When m-chlorobenzaldehyde is treated with 50% KOH solution, the product(s) obtained is (are):

1.
2.
3.
4.
Subtopic:  Acid Derivatives - Preparation, Properties & Uses |
 82%
Level 1: 80%+
AIPMT - 2003
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