The correct increasing order of ionic character of the following molecule is:
 LiF, K₂O, N₂, SO₂, ClF₃ 

1. N₂ < SO₂ < ClF₃ < K₂O < LiF

2. N₂ > SO₂ > ClF₃ > K₂O < LiF

3. N₂ > SO₂ > K₂O > ClF₃ > LiF

4. LiF > K₂O < ClF₃ > SO₂ > N₂

From the perspective of molecular orbital theory, which statement is false?

The decreasing order of ionic character of the N-H, F-H, C-H, and O-H, is :  

The number of (i) sp² hybridized carbon atoms and (ii) $\mathrm{\pi }$ bonds are present in the following compound are:

1. 7, 5

2. 8, 6

3. 7, 6

4. 8, 5

In $P{O}_4^{-3}$, formal charge on every oxygen atom and P-O bond order respectively are:
1.  -0.75 and 1.25
2.  -0.5 and 2
3.  1 and 1.5
4.  -0.75 and 2

In a regular octahedral molecule, MX₆, the number of X–M–X bonds at 180º is:

In NO₃^– ion, the number of bond pair and lone pair of electrons on nitrogen atom are respectively:

The incorrect statements among the following are-

Combination of atoms A and B that forms an anti-bonding molecular orbital is :

1. $\frac{{\mathrm{\Psi }}_{\mathrm{A}}^2}{{\mathrm{\Psi }}_{\mathrm{B}}^2}$

2. ${\mathrm{\Psi }}_{\mathrm{A}}^2\times {\mathrm{\Psi }}_{\mathrm{B}}^2$

3. ${\mathrm{\Psi }}_{\mathrm{A}}+{\mathrm{\Psi }}_{\mathrm{B}}$

4. ${\mathrm{\Psi }}_{\mathrm{A}}-{\mathrm{\Psi }}_{\mathrm{B}}$

Match List - I with List - II

Choose the correct answer from the options given below: