BF3 is a planar and an electron deficient compound. Hybridization and number of electrons around the central atom, respectively are:
1. sp2 and 6
2. sp2 and 8
3. sp3 and 4
4. sp3 and 6
Which of the compounds given below will exhibit a linear structure?
| 1. | NO2 | 2. | HOCl |
| 3. | O3 | 4. | N2O |
Match the coordination number and type of hybridization with the distribution of hybrid orbitals in space based on Valence bond theory.
| Coordination number and type of hybridisation | Distribution of hybrid orbitals in space | ||
| (a) | 4, sp3 | (i) | Trigonal bipyramidal |
| (b) | 4, dsp2 | (ii) | Octahedral |
| (c) | 5, sp3d | (iii) | Tetrahedral |
| (d) | 6, d2sp3 | (iv) | Square planar |
| (a) | (b) | (c) | (d) | |
| 1. | (ii) | (iii) | (iv) | (i) |
| 2. | (iii) | (iv) | (i) | (ii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iii) | (i) | (iv) | (ii) |
| List I Molecule |
List II Shape or geometry of the molecule |
|
| a. | PCl5 | Trigonal |
| b. | SF6 | Octahedral |
| c. | BeCl2 | Linear |
| d. | NH3 | Trigonal pyramidal |
| 1. | b | 2. | c |
| 3. | d | 4. | a |
Find the following for the given compound:
(i) sp2 hybridised carbon atoms
(ii) bonds
| 1. | 7, 5 | 2. | 8, 6 |
| 3. | 7, 6 | 4. | 8, 5 |