Q. No.The ratio of the longest wavelengths corresponding to the Lyman and Balmer series in the hydrogen spectrum is:
| 1. | \(\dfrac{3}{23}\) | 2. | \(\dfrac{7}{29}\) |
| 3. | \(\dfrac{9}{31}\) | 4. | \(\dfrac{5}{27}\) |
Subtopic: Spectral Series |
89%
From NCERT
AIPMT - 2013
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A hydrogen atom is excited from the ground state to the state of the principal quantum number \(4.\) Then the number of spectral lines observed will be:
1. \(3\)
2. \(6\)
3. \(5\)
4. \(2\)
1. \(3\)
2. \(6\)
3. \(5\)
4. \(2\)
Subtopic: Spectral Series |
87%
From NCERT
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When an electron transitions from \(n=4\) to \(n=2,\) then the emitted line in the spectrum will be:
| 1. | the first line of the Lyman series. |
| 2. | the second line of the Balmer series. |
| 3. | the first line of the Paschen series. |
| 4. | the second line of the Paschen series. |
Subtopic: Spectral Series |
87%
From NCERT
AIPMT - 2000
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Given that the value of the Rydberg constant is \(10^{7}~\text{m}^{-1},\) what will be the wave number of the last line of the Balmer series in the hydrogen spectrum?
1. \(0.5 \times 10^{7}~\text{m}^{-1}\)
2. \(0.25 \times 10^{7} ~\text{m}^{-1}\)
3. \(2.5 \times 10^{7}~\text{m}^{-1}\)
4. \(0.025 \times 10^{4} ~\text{m}^{-1}\)
1. \(0.5 \times 10^{7}~\text{m}^{-1}\)
2. \(0.25 \times 10^{7} ~\text{m}^{-1}\)
3. \(2.5 \times 10^{7}~\text{m}^{-1}\)
4. \(0.025 \times 10^{4} ~\text{m}^{-1}\)
Subtopic: Spectral Series |
87%
From NCERT
NEET - 2016
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In an atom, if the transition from \(n = 4\) to \(n=3\) gives ultraviolet radiation, then to obtain infrared radiation, the transition should be:
| 1. | \(5\rightarrow 4\) | 2. | \(3\rightarrow 2\) |
| 3. | \(2\rightarrow 1\) | 4. | \(3\rightarrow 1\) |
Subtopic: Spectral Series |
79%
From NCERT
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If the wavelength of the first line in the Balmer Series of the hydrogen spectrum is \(\lambda,\) then what is the wavelength of the second line in this series?
1. \(\frac{20}{27}\lambda\)
2. \(\frac{27}{20}\lambda\)
3. \(\frac{25}{27}\lambda\)
4. \(\frac{27}{25}\lambda\)
1. \(\frac{20}{27}\lambda\)
2. \(\frac{27}{20}\lambda\)
3. \(\frac{25}{27}\lambda\)
4. \(\frac{27}{25}\lambda\)
Subtopic: Spectral Series |
77%
From NCERT
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The wavelength of the first line of the Lyman series for a hydrogen atom is equal to that of the second line of the Balmer series for a hydrogen-like ion. What is the atomic number \(Z\) of hydrogen-like ions?
1. \(4\)
2. \(1\)
3. \(2\)
4. \(3\)
Subtopic: Spectral Series |
75%
From NCERT
AIPMT - 2011
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In the diagram shown below, two atomic transitions are shown. If \(\lambda_1= 3000~\mathring{A}\) and \(\lambda_2= 6000~\mathring{A},\)
1. \(2000~\mathring{A}\)
2. \(4000~\mathring{A}\)
3. \(4500~\mathring{A}\)
4. \(9000~\mathring{A}\)
Subtopic: Spectral Series |
74%
From NCERT
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The ionisation potential of the hydrogen atom is \(13.6~\text{eV}.\) The hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy of \(12.1~\text{eV}.\) According to Bohr’s theory, the spectral lines emitted by hydrogen atoms will be:
1. two
2. three
3. four
4. one
Subtopic: Spectral Series |
71%
From NCERT
AIPMT - 2006
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The frequency of the series limit of the Balmer series of hydrogen atoms in terms of the Rydberg constant \(R\) and velocity of light \(C\) is:
1. \(\frac{RC}{4}\)
2. \(RC\)
3. \(\frac{4}{RC}\)
4. \(4RC\)
1. \(\frac{RC}{4}\)
2. \(RC\)
3. \(\frac{4}{RC}\)
4. \(4RC\)
Subtopic: Spectral Series |
72%
From NCERT
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