| 1. | \(F_1=qE,~F_2=QE\) | 2. | \(F_1=2qE,~F_2=QE\) |
| 3. | \(F_1=2qE,~F_2={\Large\frac{QE}{2}}\) | 4. | \(F_1=qE,~F_2={\Large\frac{QE}{2}}\) |
| 1. | \(E_K=E\) | 2. | \({\Large\frac{E_K}{E}}=K\) |
| 3. | \({\Large\frac{E_K}{E}}={\large\frac{1}{K}}\) | 4. | \({\Large\frac{E_K}{E}}=\sqrt K\) |
| 1. | \(k{\Large\frac{2qQ}{\big(d^2/4\big)}}\) | 2. | \({\Large\frac{qQ}{\varepsilon_0A}}\) |
| 3. | \({\Large\frac{2qQ}{\varepsilon_0A}}\) | 4. | zero |
| 1. | \(\dfrac{E_0}{2}\) | 2. | \(\dfrac{E_0}{4}\) |
| 3. | \(\dfrac{3E_0}{4}\) | 4. | \(\dfrac{3E_0}{8}\) |
| 1. | \(10\) nF | 2. | \(20\) nF |
| 3. | \(40\) nF | 4. | none of the above |
| Statement I: | If a charged particle is taken along the \(x\)-axis, no work will be done by the electric field. |
| Statement II: | This electric field is conservative in nature i.e. it can be derived from a potential: \(V(x,y)=C-Kxy\) |
| 1. | Statement I is incorrect and Statement II is correct. |
| 2. | Both Statement I and Statement II are correct. |
| 3. | Both Statement I and Statement II are incorrect. |
| 4. | Statement I is correct and Statement II is incorrect. |