- 1(current)
Q. No.A point mass \(m\) is moved in a vertical circle of radius \(r\) with the help of a string. The velocity of the mass is \(\sqrt{7gr} \) at the lowest point. The tension in the string at the lowest point is:
| 1. | \(6 \text{mg}\) | 2. | \(7 \text{mg}\) |
| 3. | \(8 \text{mg}\) | 4. | \( \text{mg}\) |
One end of the string of length \(l\) is connected to a particle of mass \(m\) and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in a circle with speed \(v\), the net force on the particle (directed towards the center) will be: (\(T\) represents the tension in the string)
| 1. | \(T+\dfrac{m v^2}{l}\) | 2. | \(T-\dfrac{m v^2}{l}\) |
| 3. | zero | 4. | \(T\) |
A small mass attached to a string rotates on a frictionless table top as shown. If the tension in the string is increased by pulling the string causing the radius of the circular motion to decrease by a factor of 2, the kinetic energy of the mass will:
1. decrease by a factor of 2
2. remain constant
3. increase by a factor of 2
4. increase by a factor of 4
A mass is performing a vertical circular motion (see figure.) If the average velocity of the particle is increased, then at which point the string will break?
| 1. | A | 2. | B |
| 3. | C | 4. | D |
- 1(current)
Q. No.
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