- 1(current)
Q. No.If \(F=\alpha t^2-\beta t \) is the magnitude of the force acting on a particle at an instant \(t\) then the time, at which the force becomes constant, is (where \(\alpha \) and \(\beta \) are constants):
1. \(\dfrac{\beta}{\alpha}\)
2. \(\dfrac{\beta}{2\alpha}\)
3. \(\dfrac{2\beta}{\alpha}\)
4. zero
1. \(\dfrac{\beta}{\alpha}\)
2. \(\dfrac{\beta}{2\alpha}\)
3. \(\dfrac{2\beta}{\alpha}\)
4. zero
Subtopic: Â Types of Forces |
 69%
From NCERT
NEET - 2024
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.