The oxidation number of the atom (in bold) in the following species is given. Identify, which one is incorrectly related?

1. \(\mathbf{Cu}_{2} O\) is \(- 1\)

2. \(\mathbf{Cl} O_{3}^{-}\) is \(+ 5\)

3. \(K_{2} \mathbf{Cr}_{2} O_{7}\) is \(+ 6\)

4. \(H \mathbf{Au} Cl_{4}\) is \(+ 3\)

Subtopic:  Oxidizing & Reducing Agents |
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In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?
Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)

1. ClO- 

2. Cl2

3. Cl-

4. Both ClO- and Cl-

Subtopic:  Oxidizing & Reducing Agents |
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Why does the MnO₄²⁻ ion undergo disproportionation in an acidic medium, whereas the MnO₄⁻ ion does not?
1.  Due to manganese being in its highest oxidation state in MnO₄²⁻.
2.  Due to manganese being in its highest oxidation state in MnO₄⁻
3.  Because the disproportionation reaction of MnO₄²⁻ is endothermic.
4.  Because the disproportionation reaction of MnO₄²⁻ is exothermic.
Subtopic:  Introduction to Redox and Oxidation Number |
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Nitric acid reacts with PbO but does not react with PbO, because -

1. PbO is a base while PbO2 is a strong oxidizing reagent

2. PbO is a base while PbO2 is a weak oxidizing reagent

3. PbO is neutral while PbO2 is a strong oxidizing reagent

4. PbO is acid while PbO2 is a strong oxidizing reagent

Subtopic:  Oxidizing & Reducing Agents |
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The oxidation state of P in HPO32- is-

1. +3 2. +4
3. +2 4. +5
Subtopic:  Introduction to Redox and Oxidation Number |
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The oxidation state of two S-atoms in Na2S2O3 is:

1. +2 and +4

2. +3 and -2

3. +4 and -2

4. +6 and -2

Subtopic:  Introduction to Redox and Oxidation Number |
Level 3: 35%-60%
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Among the following, identify the species with an atom in +6 oxidation state-

1. MnO4-

2. Cr(CN)63-

3. NiF62-

4. CrO2Cl2

Subtopic:  Oxidizing & Reducing Agents |
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Which of the following does not represent a redox reaction?

1. Cr2O72- + 2OH- → CrO42- + H2O

2. SO42- + 2I- + 2H+ → I2 + H2S + H2O

3. Ca + 2H2O → Ca(OH)2 + H2

4. PCl5 → PCl3 + Cl2

Subtopic:  Oxidizing & Reducing Agents |
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The oxidation number of phosphorous in ATP (adenosine triphosphate) is -

1. 2 2. 3
3. 4 4. 5
Subtopic:  Oxidizing & Reducing Agents |
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Consider the standard electrode potentials given below:
(a) \(E_{k^+/K}^o = - 2.93\ V\); \(E_{Ag^+/Ag}^o = 0.80\ V\)
(b) \(E_{Hg^{2+}/Hg}^o = 0.79\ V\); \(E_{Mg^{2+}/Mg}^o = - 2.37\ V\)  
(c) \(E_{Cr^{3+}/Cr}^o = -0.74\ V\)


The correct arrangement of increasing order for reducing power of elements is:

1. \(\mathrm{Ag}<\mathrm{Hg}<\mathrm{Cr}<\mathrm{Mg}<\mathrm{K} \)
2. \(\mathrm{Ag}>\mathrm{Cr}>\mathrm{Mg}>\mathrm{Hg}>\mathrm{K}\)
3. \(\mathrm{K}>\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}>\mathrm{Ag} \)
4. \(\mathrm{K}<\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}<\mathrm{Ag}\)
Subtopic:  Emf & Electrode Potential |
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